tính nhanh
1; 20182-2017*2019
2; 20012
3;19992
4;113
5; 193
6;57*63
7; 953 + 3*952*5+3*95*52+53
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\(\dfrac{1}{3}\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right)=\dfrac{1}{3}\times1=\dfrac{1}{3}\)
Ta có: \(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+...+\dfrac{1}{9702}\)
\(=\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+...+\dfrac{1}{98\cdot99}\)
\(=\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{98}-\dfrac{1}{99}\)
\(=\dfrac{1}{3}-\dfrac{1}{99}\)
\(=\dfrac{32}{99}\)
Giải:
1/12+1/20+1/30+...+1/9702
=1/3.4+1/4.5+1/5.6+...+1/98.99
=1/3-1/4+1/4-1/5+1/5-1/6+...+1/98-1/99
=1/3-1/99
=32/99
Chúc bạn học tốt!
`a, 126^2 - 152 . 126 + 5776.`
`= 126^2 - 2 . 76 . 126 + 76^2`
`= (126+76)^2 = 202^2 = 40804`
`b, 3^8 . 5^8 - (15^4-1)(15^4+1)`
`= 15^8 - 15^8 + 1`
`= 1`
Đặt A=1x3+3x5+5x7+7x9+...+99x101
6A=6x(1x3+3x5+5x7+7x9+...+99x101)
6A=1x3x6+3x5x6+5x7x6+7x9x6+...+99x101x6
6A=1x3x(5+1)+3x5x(7-1)+5x7x(9-3)+7x9x(11-5)+...+99x101x(103-97)
6A=1x3x5+1x3+3x5x7-3x5+5x7x9-3x5x7+7x9x11-5x7x9+...+99x101x103-99x101x97
6A=3+99x101x103
=>A=\(\frac{\text{3+99x101x103}}{6}\)
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}\)
\(=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}\)
\(=\dfrac{1}{1}\cdot\dfrac{1}{2}+\dfrac{1}{2}\cdot\dfrac{1}{3}+\dfrac{1}{3}\cdot\dfrac{1}{4}+\dfrac{1}{4}\cdot\dfrac{1}{5}+\dfrac{1}{5}\cdot\dfrac{1}{6}+\dfrac{1}{6}\cdot\dfrac{1}{7}\)
\(=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}\)
\(=\dfrac{1}{1}-\dfrac{1}{7}=\dfrac{7}{7}-\dfrac{1}{7}=\dfrac{6}{7}\)
1 + 4 + 7 + 10 + 13 + 16 + 19 = 70
34 + 77 - 66 + 13 = 58
\(\dfrac{1}{7}\times\dfrac{21}{8}-\dfrac{3}{8}\times\dfrac{1}{7}-\dfrac{1}{7}\times\dfrac{2}{8}\\ =\dfrac{1}{7}\times\left(\dfrac{21}{8}-\dfrac{3}{8}-\dfrac{2}{8}\right)\\ =\dfrac{1}{7}\times\dfrac{16}{8}\\ =\dfrac{1}{7}\times2\\ =\dfrac{2}{7}\)
\(\dfrac{1}{7}\times\dfrac{21}{8}-\dfrac{3}{8}\times\dfrac{1}{7}-\dfrac{1}{7}\times\dfrac{2}{8}\)
=\(\dfrac{1}{7}\times\left(\dfrac{21}{8}-\dfrac{3}{8}-\dfrac{2}{8}\right)\)
=\(\dfrac{1}{7}\times2\)
=\(\dfrac{2}{7}\)
1. 20182 - 2017.2019 = 20182 - ( 2018 - 1 )( 2018 + 1 ) = 20182 - ( 20182 - 12 ) = 20182 - 20182 + 12 = 1
2. 20012 = ( 2000 + 1 )2 = 20002 + 2.2000.1 + 12 = 4 000 000 + 4000 + 1 = 4 004 001
3. 19992 = ( 2000 - 1 )2 = 20002 - 2.2000.1 + 12 = 4 000 000 - 4000 + 1 = 3 996 001
4. 113 = ( 10 + 1 )3 = 103 + 3.102.1 + 3.10.12 + 13 = 1000 + 300 + 30 + 1 = 1331
5. 193 = ( 20 - 1 )3 = 203 - 3.202.1 + 3.20.1 - 13 = 8000 - 1200 + 60 - 1 = 6859
6. 57.63 = ( 60 - 3 )( 60 + 3 ) = 602 - 32 = 3600 - 9 = 3591
7. 953 + 3.952.5 + 3.95.52 + 53 = ( 95 + 5 )3 = 1003 = 1 000 000
làm đúng nha