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tìm n biết
-3/5 mũ n chia 9/25 mũ 3=-3/5
\(\left(\frac{-3}{5}\right)^n:\left(\frac{9}{25}\right)^3=-\frac{3}{5}\)
=> \(\left(-\frac{3}{5}\right)^n:\left[\left(-\frac{3}{5}\right)^2\right]^3=-\frac{3}{5}\)
=> \(\left(-\frac{3}{5}\right)^n:\left(-\frac{3}{5}\right)^6=-\frac{3}{5}\)
=> \(\left(-\frac{3}{5}\right)^n=\left(-\frac{3}{5}\right)^7\)
=> n = 7
\(\frac{\left(-\frac{3}{5}\right)^n}{\left(\frac{9}{25}\right)^n}=-\frac{3}{5}\)
\(\left(-\frac{\frac{3}{5}}{\frac{9}{25}}\right)^n=-\frac{3}{5}\)
\(-\left(\frac{5}{3}\right)^n=-\frac{3}{5}\)
\(\left(\frac{5}{3}\right)^n=\frac{3}{5}\)
Vậy n = -1
\(\left(\frac{-3}{5}\right)^n:\left(\frac{9}{25}\right)^3=-\frac{3}{5}\)
=> \(\left(-\frac{3}{5}\right)^n:\left[\left(-\frac{3}{5}\right)^2\right]^3=-\frac{3}{5}\)
=> \(\left(-\frac{3}{5}\right)^n:\left(-\frac{3}{5}\right)^6=-\frac{3}{5}\)
=> \(\left(-\frac{3}{5}\right)^n=\left(-\frac{3}{5}\right)^7\)
=> n = 7
\(\frac{\left(-\frac{3}{5}\right)^n}{\left(\frac{9}{25}\right)^n}=-\frac{3}{5}\)
\(\left(-\frac{\frac{3}{5}}{\frac{9}{25}}\right)^n=-\frac{3}{5}\)
\(-\left(\frac{5}{3}\right)^n=-\frac{3}{5}\)
\(\left(\frac{5}{3}\right)^n=\frac{3}{5}\)
Vậy n = -1