Baif 1a)\(\frac{1}{42}.16^x=8^x\)b)\(3^{-3}.3^5.3^x=3^8\)c)\(\left(7x+2\right)^{-1}=3^{-2}\)Bài 2a)\(3^4.\frac{1}{729}.81^3.\frac{1}{9^2}\)b)\(\left(8.2^5\right):\left(2^4.\frac{1}{32}\right)\)c)\(12^8.9^{12}\)d)\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)Giups mik...
Đọc tiếp
Baif 1
a)\(\frac{1}{42}.16^x=8^x\)
b)\(3^{-3}.3^5.3^x=3^8\)
c)\(\left(7x+2\right)^{-1}=3^{-2}\)
Bài 2
a)\(3^4.\frac{1}{729}.81^3.\frac{1}{9^2}\)
b)\(\left(8.2^5\right):\left(2^4.\frac{1}{32}\right)\)
c)\(12^8.9^{12}\)
d)\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)
Giups mik nha
Câu a) số lớn lắm
b) \(3^{-3}\cdot3^5\cdot3^x=3^8\)
=> \(\frac{1}{27}\cdot3^5\cdot3^x=3^8\)
=> \(\frac{1}{27}\cdot3^x=3^3\)
=> \(3^x=3^3:\frac{1}{27}=3^3:\left(\frac{1}{3}\right)^3=3^3:\frac{1^3}{3^3}=3^3\cdot3^3=3^6\)
=> x = 6
b) \(\left(7x+2\right)^{-1}=3^{-2}\)
=> \(\frac{1}{7x+2}=\frac{1}{9}\)
=> 7x + 2 = 9
=> 7x = 7
=> x = 1
Bài 2:
a) \(3^4\cdot\frac{1}{729}\cdot81^3\cdot\frac{1}{9^2}\)
\(=3^4\cdot\left(\frac{1}{3}\right)^6\cdot\left(3^4\right)^3\cdot\left(\frac{1}{3}\right)^4\)
\(=3^4\cdot\left(\frac{1}{3}\right)^6\cdot3^{12}\cdot\left(\frac{1}{3}\right)^4=3^{16}\cdot\left(\frac{1}{3}\right)^{10}=\frac{3^{16}}{3^{10}}=3^6\)
b) \(\left(8\cdot2^5\right):\left(2^4\cdot\frac{1}{32}\right)=\left(2^3\cdot2^5\right):\left(2^4\cdot\left(\frac{1}{2}\right)^5\right)\)
\(=2^8:\left(2^4\cdot\frac{1^5}{2^5}\right)=2^8:\left(\frac{2^4}{2^5}\right)=2^8:2^{-1}=512\)
c) \(12^8\cdot9^{12}=\left(2^2\cdot3\right)^8\cdot\left(3^2\right)^{12}=2^{16}\cdot3^8\cdot3^{24}=2^{16}\cdot3^{32}\)
d) Tương tự
Trả lời rõ cho mik có đc k mn