-3/4:(x+1)+5/2=175%–12/5
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1)
a) \(\left(-175\right)-123+3+175+\left(-3\right)\)
\(=\left[\left(-175\right)+175\right]+\left[3+\left(-3\right)\right]-123\)
\(=0+0-123\)
\(=-123\)
b) \(17.85+15.17-150\)
\(=17.\left(85+15\right)-150\)
\(=17.100-150\)
\(=1700-150\)
\(=1550\)
c) \(176:\left(4.5^2-3.2^2\right)\)
\(=176:\left(4.25-3.4\right)\)
\(=176:\left(100-12\right)\)
\(=176:88\)
\(=2\)
2)
a) \(8-x=-12\)
\(\Rightarrow x=8-\left(-12\right)\)
\(\Rightarrow x=8+12\)
\(\Rightarrow x=20\)
Vậy \(x=20\)
b) \(20+2^3.x=5^2.4\)
\(\Rightarrow20+8.x=25.4\)
\(\Rightarrow20+8.x=100\)
\(\Rightarrow8.x=100-20\)
\(\Rightarrow8.x=80\)
\(\Rightarrow x=80:8\)
\(\Rightarrow x=10\)
Vậy \(x=10\)
c) \(2\left|x-1\right|+5=15\)
\(\Rightarrow2\left|x-1\right|=15-5\)
\(\Rightarrow2\left|x-1\right|=10\)
\(\Rightarrow\left|x-1\right|=10:2\)
\(\Rightarrow\left|x-1\right|=5\)
Xét trường hợp 1: \(x-1=5\)
\(\Rightarrow x=5+1\)
\(\Rightarrow x=6\)
Xét trường hợp 2: \(x-1=-5\)
\(\Rightarrow x=\left(-5\right)+1\)
\(\Rightarrow x=-5+1\)
\(\Rightarrow x=-\left(5-1\right)\)
\(\Rightarrow x=-4\)
Vậy \(x=6\) hoặc \(x=-4\)
Bài 1:
\(a)\left(-175\right)-123+3+175+\left(-3\right)\)
\(=\left[\left(-175\right)+175\right]+\left[\left(-3+3\right)\right]-123\)
\(=0+0-123\)
\(=-123\)
\(b)17.85+15.17-150\)
\(=17.\left(85+15\right)-150\)
\(=17.100-150=1700-150=1550\)
\(c)176:\left(4.5^2-3.2^2\right)\)
\(=176:\left(4.25-3.4\right)\)
\(=176:\left(100-12\right)=176:88=2\)
Bài 2:
\(a)8-x=-12\)
\(\Rightarrow x=8-\left(-12\right)\)
\(\Rightarrow x=20\)
\(b)20+2^3.x=5^2.4\)
\(\Rightarrow20+8.x=25.4\)
\(\Rightarrow20+8.x=100\)
\(\Rightarrow8.x=100-20\)
\(\Rightarrow8.x=80\)
\(\Rightarrow x=80:8=10\)
\(c)2\left|x-1\right|+5=15\)
\(\Rightarrow2\left|x-1\right|=15-5\)
\(\Rightarrow2\left|x-1\right|=10\)
\(\Rightarrow\left|x-1\right|=10:2\)
\(\Rightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)
b, 3/5 + 4/7 + 2/8 + 10/25 + 9/21 + 28/16
= 3/5 + 4/7 + 2/8 + 2/5 + 3/7 + 14/8
= (3/5 + 2/5) + ( 4/7 + 3/7) + ( 2/8 + 14/8)
= 1 + 1 + 7/4
= 2 + 7/4 = 15/4
c , 8/7 + 7/6 + 5/8 + 10/12 + 24/28 + 6/16
= c , 8/7 + 7/6 + 5/8 + 5/6 + 6/7 + 1/2
= (8/7 + 6/7) + (7/6 + 5/6) + 5/8 + 1/2
= 14/7 + 12/6 + 5/8 + 1/2
= 2 + 2 + 5/8 + 1/2
= 4 + 9/8 = 41/8
a)13-2(x+1)=7
2.(x+1)=13-7
2.(x+1)=6
x+1=6/2
x+1=3
x=3-1
x=2
a, 13 - 2 ( x + 1 ) = 7
2 .( x + 1 ) = 13 - 7
2 .( x + 1 ) = 6
x + 1 = 6 : 2
x + 1 = 3
x = 3 - 1
x = 4
a, => 3^x.(6+4.3) = 100-72
=> 3^x.18 = 18
=> 3^x = 18:18 = 1
=> 3^x = 3^0
=> x=0
b, => 5^x.(5+4.5) = -12+175-38
=> 5^x.25 = 125
=> 5^x = 125:25 = 5
=> 5^x = 5^1
=> x=1
Tk mk nha
a) \(6\cdot3^x+4\cdot3^{x+1}=100+\left(-72\right)\)
\(\Leftrightarrow6\cdot3^x+4\cdot3^x\cdot3=100-72\)
\(\Leftrightarrow6\cdot3^x+12\cdot3^x=28\)
\(\Leftrightarrow18\cdot3^x=28\Leftrightarrow3^x=\frac{14}{9}\)
Phần a) bn xem lại đề bài nhé!!
b) \(5\cdot5^x+4\cdot5^{x+1}=\left(-12\right)+175+\left(-38\right)\)
\(\Leftrightarrow5^{x+1}+4\cdot5^{x+1}=175-12-38\)
\(\Leftrightarrow5\cdot5^{x+1}=125\Leftrightarrow5^{x+1}=25\)
\(\Leftrightarrow5^{x+1}=5^2\Leftrightarrow x+1=2\Leftrightarrow x=1\)
Vậy x=1
a/ (ghi lại cái đề)
=>+ 3x-7=2
3x=2+7=9
x=3
+ 3x-7=-2
3x=-2+7=5
x=\(\frac{5}{3}\)
b/ (5x-10)2=100
=> +5x-10=10
5x=10+10=20
x=4
+ 5x-10=-10
5x=-10+10=0
x=0
\(\left(d\right)30-x=200-175\)
\(30-x=25\)
\(x=5\)
\(\left(e\right)5\left(x+12\right)=70\)
\(x+12=14\)
\(x=2\)
tương tự 2 câu trên bạn tự làm câu cuối nhé, mình không ghi lại đề đâu
#quankun^^