Question

[Minh Tâm Vũ]

Tính các tích sau:

a) 5xy.(-2bx²y)

b) \(\left(\frac{-4}{5}ab^2c\right)\left(-20a^4bx\right)\)

c) \(^{2^3abc.\frac{1}{4}a^2bc^3}\)

d) \(a^3b^3a^2b^2c\)

e) \(2ab.\frac{4}{3}a^2b^4.7abc\)

f) \(\left(-1,5ab^2\right)\frac{1}{4}bca^2b\)

***Lm giúp mk vs mk cần gấp<3

Answer 1

[Huỳnh Quang Sang]

a) \(5xy\cdot\left(-2bx^2y\right)=-10b\left(x\cdot x^2\right)\left(y\cdot y\right)=-10bx^3y^2\)

b) \(\left(-\frac{4}{5}ab^2c\right)\left(-20a^4bx\right)=\left[\left(-\frac{4}{5}\right)\cdot\left(-20\right)\right]\left(a\cdot a^4\right)\left(b^2\cdot b\right)cx\)

\(=16a^5b^3cx\)

c) \(2^3abc\cdot\frac{1}{4}a^2bc^3=8abc\cdot\frac{1}{4}a^2bc^3=2\left(a\cdot a^2\right)\left(b\cdot b\right)\left(c\cdot c^3\right)=2a^3b^2c^4\)

Answer 2

[Huỳnh Quang Sang]

d) \(a^3b^3a^2b^2c=\left(a^3\cdot a^2\right)\left(b^3\cdot b^2\right)c=a^5b^5c\)

e) \(2ab\cdot\frac{4}{3}a^2b^4\cdot7abc=\left(2\cdot\frac{4}{3}\cdot7\right)\left(a\cdot a^2\cdot a\right)\left(b\cdot b^4\cdot b\right)c=\frac{56}{3}a^4b^6c\)

f) \(\left(-1,5ab^2\right)\cdot\frac{1}{4}bca^2b=\left(-1,5\cdot\frac{1}{4}\right)\left(a\cdot a^2\right)\left(b^2\cdot b\cdot b\right)c=-\frac{3}{8}a^3b^4c\)