Question

[ミ★Áℭ❖𝔔𝔲ỷ❖²⁰⁰⁹ 亗 ╰‿╯꧁ℭ𝔇꧂]

     giúp với nha mn

Answer 1

[Member lỗi thời :>>]

\(\frac{8^5.\left(-5\right)^8+\left(-2\right)^5.10^9}{2^{16}.5^7+20^8}\)

\(=\frac{\left(2^3\right)^5.5^8+\left(-1\right)^5.2^5.\left(2.5\right)^9}{2^{16}.5^7+\left(2^2.5\right)^8}\)

\(=\frac{2^{15}.5^8+\left(-1\right).2^5.2^9.5^9}{2^{16}.5^7+\left(2^2\right)^8.5^8}\)

\(=\frac{2^{15}.5^8+\left(-1\right).2^{14}.5^9}{2^{16}.5^7+2^{16}.5^8}\)

\(=\frac{2^{14}.5^8.\left(2-1-5\right)}{2^{16}.5^7.\left(1+5\right)}\)

\(=\frac{5.\left(-4\right)}{2^2.6}=\frac{-20}{24}=\frac{-5}{6}\)

Answer 2

[Member lỗi thời :>>]

Mình nhầm xíu :

\(\frac{8^5.\left(-5\right)^8+\left(-2\right)^5.10^9}{2^{16}.5^7+20^8}=\frac{\left(2^3\right)^5.5^8+\left(-1\right)^5.2^5.\left(2.5\right)^9}{2^{16}.5^7+\left(2^2.5\right)^8}\)

\(=\frac{2^{15}.5^8+\left(-1\right).2^5.2^9.5^9}{2^{16}.5^7+\left(2^2\right)^8.5^8}\)\(=\frac{2^{15}.5^8+\left(-1\right).2^{14}.5^9}{2^{16}.5^7+2^{16}.5^8}\)

\(=\frac{2^{14}.5^8.\left(2-1.5\right)}{2^{16}.5^7.\left(1+5\right)}\)\(=\frac{5.\left(-3\right)}{2^2.6}=\frac{-15}{24}=\frac{-5}{8}\)