\(\frac{112}{23}\)+\(\frac{345}{23}\)+\(\frac{145}{23}\)+\(\frac{666}{23}\)
K
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KN
2
JS
16 tháng 2 2020
Giải:
Ta có: \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)\)
\(\Leftrightarrow x-23=0\) (Vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\) ≠ 0)
\(\Leftrightarrow x=23\)
Vậy nghiệm của phương trình là x = 23.
Chúc bạn học tốt@@
8 tháng 4 2020
\(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\Leftrightarrow x-23=0\Leftrightarrow x=23\)
Vậy $x=23$
2 tháng 7 2016
\(M=\frac{2.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{23}\right)}{-5.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{23}\right)}+\frac{\frac{1}{17}-\frac{1}{23}+\frac{1}{31}}{3.\left(\frac{1}{17}-\frac{1}{23}+\frac{1}{31}\right)}=-\frac{2}{5}+\frac{1}{3}=\frac{1}{15}.\)
22 tháng 6 2020
=\(\frac{-11}{23}\)\(\times\)\(\frac{10}{-13}\)\(+\)\(\frac{11}{-13}\)\(\times\)\(\frac{-3}{23}\)\(+\)\(\frac{12}{23}\)
=\(\frac{110}{299}\)\(+\)\(\frac{33}{299}\)\(+\)\(\frac{12}{23}\)
=\(\frac{143}{299}\)\(+\)\(\frac{12}{23}\)
= 1
PT
2
YN
3 tháng 4 2016
\(\frac{-11}{23}\cdot\frac{6}{7}+\frac{8}{7}\cdot\frac{-11}{23}-\frac{1}{23}\)
\(=\frac{-11}{23}\cdot\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)
\(=\frac{-11}{23}\cdot\frac{14}{7}-\frac{1}{23}\)
\(=\frac{-11}{23}\cdot2-\frac{1}{23}\)
\(=\frac{-22}{23}-\frac{1}{23}\)
\(=\frac{-22-1}{23}\)
\(=\frac{-23}{23}=-1\)
HQ
Hà Quang Minh
Giáo viên
19 tháng 9 2023
a)
\(\begin{array}{l}\frac{{13}}{{23}}.\frac{7}{{11}} + \frac{{10}}{{23}}.\frac{7}{{11}}\\ = \frac{7}{{11}}.\left( {\frac{{13}}{{23}} + \frac{{10}}{{23}}} \right)\\ = \frac{7}{{11}}.\frac{23}{23}\\ = \frac{7}{{11}}.1\\ = \frac{7}{{11}}\end{array}\)
b)
\(\begin{array}{l}\frac{5}{9}.\frac{{23}}{{11}} - \frac{1}{{11}}.\frac{5}{9} + \frac{5}{9}\\ = \frac{5}{9}.\left( {\frac{{23}}{{11}} - \frac{1}{{11}} + 1} \right)\\ = \frac{5}{9}.\left( {2 + 1} \right)\\ = \frac{5}{9}.3 = \frac{5}{3}\end{array}\)
c)
\(\begin{array}{l}\left[ {\left( { - \frac{4}{9} + \frac{3}{5}} \right):\frac{{13}}{{17}}} \right] + \left( {\frac{2}{5} - \frac{5}{9}} \right):\frac{{13}}{{17}}\\ = \left( { - \frac{4}{9} + \frac{3}{5}} \right).\frac{{17}}{{13}} + \left( {\frac{2}{5} - \frac{5}{9}} \right).\frac{{17}}{{13}}\\ = \frac{{17}}{{13}}.\left( { - \frac{4}{9} + \frac{3}{5} + \frac{2}{5} - \frac{5}{9}} \right)\\ = \frac{{17}}{{13}}.\left[ {\left( { - \frac{4}{9} - \frac{5}{9}} \right) + \left( {\frac{3}{5} + \frac{2}{5}} \right)} \right]\\ =\frac{{17}}{{13}}. (\frac{-9}{9}+\frac{5}{5})\\= \frac{{17}}{{13}}.\left( { - 1 + 1} \right)\\ = \frac{{17}}{{13}}.0 = 0\end{array}\)
d)
\(\begin{array}{l}\frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{3}{{11}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{2}{5}} \right)\\ = \frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{6}{{22}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{4}{{10}}} \right)\\ = \frac{3}{{16}}:\frac{{ - 3}}{{22}} + \frac{3}{{16}}:\frac{{ - 3}}{{10}}\\ = \frac{3}{{16}}.\frac{{ - 22}}{3} + \frac{3}{{16}}.\frac{{ - 10}}{3}\\ = \frac{3}{{16}}.\left( {\frac{{ - 22}}{3} + \frac{{ - 10}}{3}} \right)\\ = \frac{3}{{16}}.\frac{{ - 32}}{3}\\ = - 2\end{array}\)
NT
6
2 tháng 6 2015
\(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
=> x-23=0
x=0+23
x=23. Vậy x=23
Chúc bạn học tốt!^_^
1 tháng 6 2015
\(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
=> \(\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
=>( x-13)(\(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\) = 0
ta thấy 1/24>1/25>1/26>1/27 => 1/24+1/25 - 1/ 26 - 1/17 > 0
=> x -13 = -
=> x=13
N
1
4 tháng 5 2018
\(\dfrac{9}{23}\) x \(\dfrac{5}{8}\) + \(\dfrac{9}{23}\) x \(\dfrac{3}{8}\) - \(\dfrac{9}{23}\)= \(\dfrac{9}{23}\) x \(\left(\dfrac{5}{8}+\dfrac{3}{8}\right)-\dfrac{9}{23}\)
\(=\dfrac{9}{23}\) x \(1\) \(-\dfrac{9}{23}\)
\(=0\)
\(\frac{112}{23}+\frac{345}{23}+\frac{145}{23}+\frac{666}{23}=\left(\frac{112}{23}+\frac{666}{23}\right)+\left(\frac{345}{23}+\frac{145}{23}\right)=\frac{778}{23}+\frac{490}{23}=\frac{1268}{23}\)