14-(-15)-21
321+{-15+[30+(-321)]}
(2016+432)+[168+(-2016)]
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a)=321+15+30+(-321)
=[321+(-321)]+(15+30)
=0+45=45
b)=2016+432+168+(-2016)
=[2016+(-2016)]+(432+168)
=0+600=600
a)321+{15+[30+(-321)]}=[321+(-321)]+(15+30)=0+45=45
b)(2016+432)+[168+(-2016)]=[2016+(-2016)]+(432+168)=0+600=600
321 + { -15 + [ 30 + (-321) ] }
= 321 + { -15 + [ 30 - 321 ] }
= 321 + { -15 + 30 - 321 }
= 321 - 15 + 30 - 321
= (321 - 321) - (15 - 30)
= 0 - (-15)
= 15
(2016 + 432) + [168 + (-2016) ]
= 2016 + 432 + [ 168 - 2016 ]
= 2016 + 432 + 168 - 2016
= (2016 - 2016) + (432 + 168)
= 0 + 600
= 600
minh khong biet dau minh chi moi lop 5 thoi
chuc ban nam moi vui ve
thank you very much
( 2016 + 432 ) + [ 168 + ( - 2016 ) ]
=2016 +432+168+(-2016)
=[2016+(-2016)] +(432+168)
= 600
(2016+432)+[168+(- 2016)]
=2016+432+168+-2016
=(-2016+2016)+(432+168)
=0+600
=600
hoc tot cho 1 nha
a, Ta có :
\(A=\dfrac{15}{14}+\dfrac{16}{15}+\dfrac{17}{16}+\dfrac{18}{17}\)
\(\Leftrightarrow A=\left(1+\dfrac{1}{14}\right)+\left(1+\dfrac{1}{15}\right)+\left(1+\dfrac{1}{16}\right)+\left(1+\dfrac{1}{17}\right)\)
\(\Leftrightarrow A=\left(1+1+1+1\right)+\left(\dfrac{1}{14}+\dfrac{1}{15}+\dfrac{1}{16}+\dfrac{1}{17}\right)\)
\(\Leftrightarrow A=4+\left(\dfrac{1}{15}+\dfrac{1}{16}+\dfrac{1}{17}+\dfrac{1}{18}\right)\)
\(\Leftrightarrow A>4\)
b. \(B=\dfrac{2015}{2016}+\dfrac{2016}{2017}+\dfrac{2017}{2019}\)
\(\Leftrightarrow B=\left(1-\dfrac{1}{2016}\right)+\left(1-\dfrac{1}{2017}\right)+\left(1-\dfrac{3}{2019}\right)\)
\(\Leftrightarrow B=\left(1+1+1\right)-\left(\dfrac{1}{2016}+\dfrac{1}{2017}+\dfrac{3}{2019}\right)\)
\(\Leftrightarrow B=3-\left(\dfrac{1}{2016}+\dfrac{1}{2017}+\dfrac{3}{2019}\right)\)
\(\Leftrightarrow B< 3\)
A = 15/14 + 16/15 + 17/16 + 18/17
Ta thấy :
15/14 > 1
16/15 > 1
17/16 > 1
18/17 > 1
=> A > 4
B tương tự
\(\text{14-(-15)-21}\)
\(=14+15-21\)
\(=29-21\)
\(=8\)
\(321+\left\{-15+\left[30+\left(-321\right)\right]\right\}\)
\(=321+\left(-15\right)+30+\left(-321\right)\)
\(=\left(321+\left(-321\right)\right)+\left(\left(-15\right)+30\right)\)
\(=0+15\)
\(=15\)
\(\text{(2016+432)+[168+(-2016)]}\)
\(=2016+432+168+\left(-2016\right)\)
\(=\left[2016+\left(-2016\right)\right]+\left(432+168\right)\)
\(=0+600\)
\(=600\)
học tốt