48 x X - X + 53 x X = 7900
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48 * x - x + 53 * x = 7900
,=> x *( 48 - 1 + 53 ) = 7900
=> x * 100 = 7900
=> x = 7900 : 100
=> x = 79
Vậy x = 79
48 x X - X + 53 x X = 7900
48 x X - X x 1 + 53 x X = 7900
X x ( 48 - 1 + 53 ) = 7900
X x 100 = 7900
X = 7900 : 100
X = 79.
Vậy X = 79.
Hok tốt !
7900 x 120+ 7900 x 380 + 7900 x 500
= 7900 x ( 120 + 380 + 500 )
= 7900 x 1000
= 7900000
Thanh lý nick này, ai cần xin liên hệ
\(x\times92+x\times7+x=7900\)
\(\Rightarrow x\times\left(92+7+1\right)=7900\)
\(\Rightarrow x\times100=7900\)
\(\Rightarrow x=7900:100\)
\(\Rightarrow x=79\)
X x 92 + X x 7 + X = 7900
X x 92 + X x 7 + X x 1 = 7900
X x ( 92 + 7 + 1 ) = 7900
X x 100 = 7900
X = 7900 : 100
X = 79
N * 5 + N * 9 + N * 28 - N * 33 = 7900
N * ( 5 + 9 + 28 - 33 ) = 7900
N * 9 = 7900
N = 7900 : 9
Tick nha
N x 5 + N x 9 + N x 28 - N x 33 = 7900
N x ( 5 + 9 + 28 - 33 ) = 7900
N x 9 = 7900
N = 7900 : 9
N = đề sai
a) \(\left(145\times99+145\right)-\left(143\times102-143\right)\)
\(=\left[145\times\left(99+1\right)\right]-\left[143\times\left(102-1\right)\right]\)
\(=\left(145\times100\right)-\left(143\times101\right)\)
\(=14500-14443\)
\(=57\)
b) \(54\times47-47\times53-20-27\)
\(=47\times\left(54-53\right)-20-27\)
\(=47-20-27\)
\(=0\)
c) \(10000-47\times72-47\times28\)
\(=10000-47\times\left(72+28\right)\)
\(=10000-47\times100\)
\(=10000-4700\)
\(=5300\)
d) \(3457-27\times48-48\times73+6543\)
\(=\left(3457+6543\right)-48\times\left(27+73\right)\)
\(=10000-48\times100\)
\(=10000-4800\)
\(=5200\)
Ta có : \(\dfrac{x-50}{50}+\dfrac{x-51}{49}+\dfrac{x-52}{49}+\dfrac{x-53}{47}+\dfrac{x-200}{25}=0\)
\(\Leftrightarrow\dfrac{x-50}{50}-1+\dfrac{x-51}{49}-1+\dfrac{x-52}{49}-1+\dfrac{x-53}{47}-1+\dfrac{x-200}{25}+4=0\)
\(\Leftrightarrow\dfrac{x-100}{50}+\dfrac{x-100}{49}+\dfrac{x-100}{49}+\dfrac{x-100}{47}+\dfrac{x-100}{25}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}\right)=0\)
<=> x - 100 = 0
<=> x = 100
Vậy ..
Ta có: \(\dfrac{x-50}{50}+\dfrac{x-51}{49}+\dfrac{x-52}{48}+\dfrac{x-53}{47}+\dfrac{x-200}{25}=0\)
\(\Leftrightarrow\dfrac{x-50}{50}-1+\dfrac{x-51}{49}-1+\dfrac{x-52}{48}-1+\dfrac{x-53}{47}-1+\dfrac{x-200}{25}+4=0\)
\(\Leftrightarrow\dfrac{x-100}{50}+\dfrac{x-100}{49}+\dfrac{x-100}{48}+\dfrac{x-100}{47}+\dfrac{x-100}{25}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}\right)=0\)
mà \(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{25}>0\)
nên x-100=0
hay x=100
Vậy: S={100}
48 x X - X + 53 x X = 7900
X x ( 48 - 1 + 53 ) = 7900
X x 100 = 7900
X = 79
HOK TỐT
48x-x+53x=79000
=> x(48-1+53)=79000
=>100x=79000
=>x=79