\(\frac{7x-12}{5x-2}=\frac{9-7x}{-5x+1}\)
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\(\frac{x+\frac{2\left(3-x\right)}{5}}{14}-\frac{5x-4\left(x-1\right)}{24}=\frac{7x+2+\frac{9-3x}{5}}{12}+\frac{2}{3}\)
\(\Leftrightarrow\frac{x}{840}-\frac{17}{210}=\frac{8x}{15}+\frac{19}{60}+\frac{2}{3}\)
\(\Leftrightarrow\frac{x}{840}.840-\frac{17}{210}.840=\frac{8x}{15}.840+\frac{19}{60}.840+\frac{2}{3}.840\)
\(\Leftrightarrow x-68=448x+226+560\)
\(\Leftrightarrow x-68=448x+826\)
\(\Leftrightarrow x=448x+826+68\)
\(\Leftrightarrow x=448x+894\)
\(\Leftrightarrow-447x=894\)
=> x = -2
Ta có :
\(\frac{7x+2}{5x+7}=\frac{7x-1}{5x+1}\)
\(=>\left(7x+2\right)\left(5x+1\right)=\left(7x-1\right)\left(5x+7\right)\)
\(=>35x^2+7x+10x+2=35x^2+49x-5x-7\)
\(=>35x^2+17x+2=35x^2+44x-7\)
\(=>17x+2=44x-7\)
\(=>44x-17x=2+7\)
\(=>27x=9\)
\(=>x=\frac{9}{27}=\frac{1}{3}\)
=>(7x+2)*(5x+1)=(5x+7)(7x-1)(t/c 2 p/s bằng nhau)
7x(5x+1)+2(5x+1)=5x(7x-1)+7(7x-1)
35x2+7x+10x+2=35x2-5x+49x-7
17x+2=44x-7
17x-44x=-7-2
-27x=-9
x=-9/-27=1/3
Vậy x=1/3
\(\frac{7x-12}{5x-2}=\frac{9-7x}{-5x+1}\)
\(=>\frac{2x-10}{5x-2}+1=\frac{-7x+9}{-5x+1}=\frac{-2x+8}{-5x+1}+1\)
\(=>\frac{2x-10}{5x-2}=\frac{-2x+8}{-5x+1}=\frac{-\left(2x-8\right)}{-\left(5x-1\right)}=\frac{2x-8}{5x-1}\)
\(=>\frac{2x-10}{5x-2}=\frac{2x-8}{5x-1}\)
\(=>\frac{5x-1}{5x-2}=\frac{2x-8}{2x-10}\)
\(=>\frac{-1}{5x-2}=\frac{-2}{2x-10}\)
\(=>-2x+10=-10x+4\)
\(=>-2x+10x=4-10=-6\)
\(=>8x=-6\)
\(=>x=\frac{-6}{8}=\frac{-3}{4}\)
P/s ko chắc :v
Ta có: \(\frac{7x-12}{5x-2}=\frac{7x-9}{5x-1}\)
\(\Rightarrow\left(7x-12\right).\left(5x-1\right)=\left(7x-9\right).\left(5x-2\right)\)
\(\Leftrightarrow35x^2-7x-60x+12=35x^2-14x-45x+18\)
\(\Leftrightarrow\left(35x^2-35x^2\right)-\left(7x+60x-14x-45x\right)=18-12\)
\(\Leftrightarrow8x=6\)
\(\Leftrightarrow x=\frac{3}{4}\)
Vậy \(\Leftrightarrow x=\frac{3}{4}\)