Tìm x:
x-{x-[x-(-x+11)]}=1
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(X:\dfrac{3}{9}=\dfrac{7}{8}\)
\(X=\dfrac{7}{8}\times\dfrac{3}{9}\)
\(X=\dfrac{21}{72}\)
\(\left(X-21\times13\right):11=30\)
\(X-273=330\)
\(X=603\)
`x:3/9=7/8`
`x=7/8xx3/9`
`x=7/24`
`-------------`
`(x-21xx13):11=30`
`(x-273):11=30`
`x-273=30xx11`
`x-273=330`
`x=330-273`
`x=57`
\(\Leftrightarrow x^3+2x^2-3x-x^3-3x^2=-4\)
\(\Leftrightarrow x^2+3x-4=0\)
=>(x+4)(x-1)=0
=>x=-4 hoặc x=1
Bài 2:
Ta có: \(x\left(x-4\right)-x^2+8=0\)
\(\Leftrightarrow x^2-4x-x^2+8=0\)
\(\Leftrightarrow-4x=-8\)
hay x=2
\(x+\left(x+1\right)+\left(x+2\right)+...+19+20=20\)
\(\Leftrightarrow x+\left(x+1\right)+\left(x+2\right)+...+19=0\)
\(\Leftrightarrow\frac{x\left(19+x\right)}{2}=0\)
\(\Leftrightarrow x\left(x+19\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+19=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=-19\end{cases}}\)
Mà \(x\ne0\)nên \(x=-19\)
\(\frac{x+1}{2}=\frac{8}{x+1}\Rightarrow\left(x+1\right)^2=8.2\)
=>(x+1)2=16
=>x+1=\(\sqrt{16}\)
=>x+1=4
=>x=3
x * 2 + x * 3 + x * 4 + x = 2130
x * (2 + 3 + 4 + 1) = 2130
x * 10 = 2130
x = 2130 : 10 = 213
\(x-\left\{x-\left[x-\left(-x+11\right)\right]\right\}=1\)
\(x-\left\{x-\left[x-\left(-x\right)-11\right]\right\}=1\)
\(x-\left\{x-\left[x+x-11\right]\right\}=1\)
\(x-\left\{x-2x+11\right\}=1\)
\(x-\left\{-x+11\right\}=1\)
\(x-\left(-x\right)-11=1\)
\(x+x-11=1\)
\(2x-11=1\)
\(2x=1+11\)
\(2x=12\)
\(x=12:2\)
\(x=6\)
\(x-\left\{x-\left[-x+11\right]\right\}=1\)
\(x-\left\{x\left[x+x+11\right]\right\}=1\)
\(x-\left\{x\left[2x+11\right]\right\}=1\)
\(x-x.2x-11=1\)
\(x-x.2x=12\)
... Đến đây ko bt đúng ko nữa ...