(x-3)(2y-1) = 216
Tìm x, y thuộc N
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b: \(\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{y}{3}\right)^2=\left(\dfrac{2}{3}\right)^6\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{4}{9}\right)^3\\\left(\dfrac{y}{3}\right)^2=\left(\dfrac{8}{27}\right)^2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-\dfrac{2}{9}=\dfrac{4}{9}\\\dfrac{y}{3}=\dfrac{8}{27}\end{matrix}\right.\\\left\{{}\begin{matrix}x-\dfrac{2}{9}=\dfrac{4}{9}\\\dfrac{y}{3}=-\dfrac{8}{27}\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=\dfrac{2}{3}\\y=\dfrac{8}{9}\end{matrix}\right.\\\left\{{}\begin{matrix}x=\dfrac{2}{3}\\y=-\dfrac{8}{9}\end{matrix}\right.\end{matrix}\right.\)
c: =>8x-1=5
=>8x=6
hay x=3/4
(3-x)(2y-1)=15
Ta xét bảng sau:
3-x | 1 | -1 | 3 | -3 | 5 | -5 | 15 | -15 |
x | 2 | 4 | 0 | -6 | -2 | 8 | -12 | 18 |
2y-1 | 15 | -15 | 5 | -5 | 3 | -3 | 1 | -1 |
2y | 16 | -14 | 6 | -4 | 4 | -2 | 2 | 0 |
y | 8 | -7 | 3 | -2 | 2 | -1 | 1 | 0 |
15=1.15=3.5=-1.-15=-3.-15
nhieu nghiem qua
VD.
3-x=1=> x=2
2y-1=15=> y=8
x,y=(2,8)
.....
x + ( x + 1 ) + ( x + 2 )+.........+ (x + 30)= 1240
x + ( x . 30 ) + ( 1 + 2 + .... + 30 ) = 1240
x . 31 + ( 1 + 2 + .... + 30 ) = 1240
x.31 +[( 31-1)+1] = 1240
x.31 + [( 30+1)*30:2] = 1240
x.31 + 465 = 1240
x.31 = 1240 - 465
x.31 = 775
x = 775 : 31
x = 25
1+2+3+...+x=210
(x+1).x:2=210
(x+1).x=210.2
(x+1).x=420
(x+1).x=(20+1).20
=>x=20