Phân tích đa thức thành nhân tử theo nhiều cách
1.\(^{x^2-5x+6}\)
NHIỀU CÁCH!!!!
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(x^2+x-6=x^2-2x+3x-6=x\left(x-2\right)+3\left(x-2\right)=\left(x-2\right)\left(x+3\right)\)
\(x^2+x-6=x^2+2.\frac{1}{2}x+\frac{1}{4}-\frac{25}{4}=\left(x+\frac{1}{2}\right)^2-\frac{25}{4}=\left(x+\frac{1}{2}-\frac{5}{2}\right)\left(x+\frac{1}{2}+\frac{5}{2}\right)=\left(x-2\right)\left(x+3\right)\)
x2+x-6=x3+3x-2x-6=x(x+3)-2(x+3)=(x+3)(x-2)
x2+x-6=\(x^2+x+\frac{1}{4}-6-\frac{1}{4}=\left(x+\frac{1}{2}\right)^2-\left(\frac{5}{2}\right)^2=\left(x+\frac{1}{2}-\frac{5}{2}\right)\left(x+\frac{1}{2}+\frac{5}{2}\right)=\left(x-2\right)\cdot\left(x+3\right)\)
\(1,x^2+5x-6=x^2-x+6x-6=x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x+6\right)\)
\(3,7x-6x^2-2=-6x^2+7x-2=-6x^2+3x+4x-2=3x\left(-2x+1\right)+2\left(2x-1\right)\)
\(=3x\left(1-2x\right)-2\left(1-2x\right)=\left(1-2x\right)\left(3x-2\right)\)
\(2,5x^2+5xy-x-y=5x\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(5x-1\right)\)
cách 1 : \(x^2\)\(-\)\(5x\)\(+\)\(6\)
\(=\)\(x^2\)\(-\)\(2x\)\(-\)\(3x\)\(+\)\(6\)
\(=\)\(\left(x^2-2x\right)-\left(3x-6\right)\)
\(=\)\(x\left(x-2\right)-3\left(x-2\right)\)
\(=\)\(\left(x-3\right)\left(x-2\right)\)
Cách 2 : \(x^2\)\(-\)\(5x\)\(+\)\(6\)
\(=\)\(x^2\)\(-\)\(4x\)\(+\)\(4\)\(-\)\(x\)\(+\)\(2\)
\(=\)\(\left(x-2\right)^2\)\(-\)\(\left(x-2\right)\)
\(=\)\(\left(x-2\right)\)\(\left(x-2-1\right)\)
\(=\)\(\left(x-2\right)\left(x-3\right)\)
Mình chỉ biết một cách thôi
x^2-5x+6
=x^2-2x-3x+6
=x(x-2)-3(x-2)
=(x-3)(x-2)
\(2x^2-5x+2\)
\(=2x^2-x-4x+2\)
\(=x\left(2x-1\right)-2\left(2x-1\right)\)
\(=\left(x-2\right)\left(2x-1\right)\)
=x3-7x+6
=x3-2x2+2x2-4x-3x+6
=x2(x-2)+2x(x-2)-3(x-2)
=(x-2)(x2+2x-3)
=(x-2)(x2+2x+1-4)
=(x-2)[(x+1)2-4]
=(x-2)(x+1-2)(x+1+2)=(x-1)(x-2)(x+3)
x3 - 7x + 6
= x3 - 2x2 + 2x2 - 4x - 3x + 6
= x2 ( x - 2 ) + 2x ( x - 2 ) + 3 ( x - 2 )
= ( x2 + 2x + 3 ) ( x - 2 )
= ( x2 + 2x + 1 - 4 ) ( x - 2 )
= [ ( x + 1 )2 - 22 ] ( x - 2 )
= ( x + 1 - 2 ) ( x + 1 + 2 ) ( x - 2 )
= ( x - 1 ) ( x + 3 ) ( x - 2 )
a) \(\left(x-7\right)\left(x+2\right)\)
b) \(\left(2x-3\right)\left(x+2\right)\)
a) Ta có : x2 + 7x + 12
= x2 + 3x + 4x + 12
= (x2 + 3x) + (4x + 12)
= x(x + 3) + 4(x + 3)
= (x + 4)(x + 3)
Bạn ơi mk nhầm đề rồi số 30 thay bằng số 60 còn 36 thay bằng 72 và 39 thay bằng 75 nha