\(A=\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5+\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
K
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17 tháng 6 2019
\(A=-7+\frac{3}{4}-\frac{1}{3}-6+\frac{5}{4}-\frac{4}{3}-3-\frac{7}{4}+\frac{5}{3}\)
\(A=\left(-7-6-3\right)+\left(\frac{3}{4}+\frac{5}{4}-\frac{7}{4}\right)+\left(\frac{5}{3}-\frac{1}{3}-\frac{4}{3}\right)\)
\(A=-16+\frac{1}{4}+0\)
\(A=-15\frac{3}{4}\)
17 tháng 6 2019
\(A=\left(-7+\frac{3}{4}-\frac{1}{3}\right)-\left(6-\frac{5}{4}+\frac{4}{3}\right)-\left(3+\frac{7}{4}-\frac{5}{3}\right)\)
\(=-7+\frac{3}{4}-\frac{1}{3}-6+\frac{5}{4}-\frac{4}{3}-3-\frac{7}{4}+\frac{5}{3}\)
\(=\left(-7-6-3\right)+\left(\frac{3}{4}+\frac{5}{4}-\frac{7}{4}\right)+\left(\frac{-1}{3}-\frac{4}{3}+\frac{5}{3}\right)\)
\(=-16-\frac{1}{4}\)
31 tháng 7 2020
Trả lời:
\(A=\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5+\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
\(A=\left(\frac{36}{12}-\frac{3}{12}+\frac{8}{12}\right)-\left(\frac{75}{15}+\frac{5}{15}-\frac{18}{15}\right)-\left(\frac{24}{4}-\frac{7}{4}+\frac{6}{4}\right)\)
\(A=\frac{41}{12}-\frac{62}{15}-\frac{23}{4}\)
\(A=\frac{-97}{15}\)
Học tốt
KN
31 tháng 7 2020
\(A=\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5+\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
\(\Rightarrow A=3-\frac{1}{4}+\frac{2}{3}-5-\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(\Rightarrow A=\left(3-5-6\right)+\left(-\frac{1}{4}+\frac{7}{4}\right)+\left(\frac{2}{3}-\frac{1}{3}\right)+\frac{6}{5}-\frac{3}{2}\)
\(\Rightarrow A=-8+\frac{3}{2}+\frac{1}{3}+\frac{6}{5}-\frac{3}{2}\)
\(\Rightarrow A=-8+\frac{1}{3}+\frac{6}{5}\)
\(\Rightarrow A=-\frac{97}{15}\)
\(A=\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5+\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
\(A=3-\frac{1}{4}+\frac{2}{3}-5-\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(A=\left(3-5-6\right)+\left(-\frac{1}{4}+\frac{7}{4}-\frac{3}{2}\right)+\left(\frac{2}{3}-\frac{1}{3}\right)+\frac{6}{5}\)
\(A=\left(-8\right)+0+\frac{1}{3}+\frac{6}{5}\)
\(A=\left(-8\right)+\frac{1}{3}+\frac{6}{5}\)
\(A=\left(-\frac{23}{3}\right)+\frac{6}{5}\)
\(A=-\frac{97}{15}.\)
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