tìm 2 số tự nhiên có tích bằng 300 và BCNN là 60
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3.
Gọi hai số tự nhiên cần tìm là a và b
a.b=BCNN(a;b).ƯCLN(a;b)
hay 2700= 900.ƯCLN(a;b)
=> ƯCLN(a;b)=3
Vì ƯCLN(a;b)=3 nên a và b chia hết cho 3
Đặt a=3k ; b=3q k,q\(\in\)N và ƯCLN(k;q)=1
a.b=2700
hay 3k.3q=2700
=> 3.3.k.q=2700
=> 9.k.q=2700
=> k.q=300
SO TO QUA BAN AK XEM LAI DE DI
trong sách nâng cao và phát triển toán 6 tập 1 ở bài 328 trang 85
a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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gọi 2 số đó là a,b
vì a.b=300 mà BCNN(a,b)=60.Suy ra UCLN(a,b)=300/60=5
vì UCLN(a,b)=5.Suy ra a,b cùng chia hết cho 5
vì BCNN(a,b)=60.Suy ra a,b\(\in\) U(60)
Vậy a,b\(\in\)\(\xi\)5,10,15,20,30,60\(\xi\)
còn lại bạn tự giải nhé
Chi Chi An ơi, BCNN nghĩa là gì ? Mình ko hiểu