( 911. 2435) : ( 815 . 324)
( 93 . 210 . 275) : ( 45 . 816)
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\(a,4^9:4^4=4^5\\b,17^8:17^5=17^3\\ c,2^{10}:8^2=2^{10}:2^6=2^4\\ d,18^{10}:3^{10}=2^{10}\cdot3^{20}:3^{10}=2^{10}\cdot3^{10}=6^{10}\\ e,27^5:81^3=3^{15}:3^{12}=3^3 \)
\(f,10^6:100=10^6:10^2=10^4\\ g,5^9:25^3=5^9:5^6=5^3\\ h,4^{10}:64^3=4^{10}:4^9=4\\ i,2^{25}:32^4:18^4:9^4=2^{25}:2^{20}:2^4:3^8:3^8=2\)
a)
49:44=45
178:175=173
210:82=210:24=26
1810:310=1510
275:813=315:312=33
b)106:102=104
59:56=53
410:643=4
225:324=225:220=25
184:94=94
\(4^9:4^4\)
=\(4^{9-4}\)
=\(4^5\)
\(17^8:17^5\)
=\(17^{8-5}\)
= \(17^3\)
\(2^{10}:8^2\)
\(=2^{^{ }10}:\left(2^3\right)^2\)
=\(2^{10}:2^6\)
\(=2^4\)
\(18^{10}:3^{10}\)
=\(\left(18:3\right)^{10}\)
=\(6^{10}\)
a) \(4^9:4^4\)
\(=4^{9-4}\)
\(=4^5\)
b) \(17^8:17^5\)
\(=17^{8-5}\)
\(=17^3\)
c) \(2^{10}:8^2\)
\(=2^{10}:\left(2^3\right)^2\)
\(=2^{10-6}\)
\(=2^4\)
d) \(18^{10}:3^{10}\)
\(=\left(18:3\right)^{10}\)
\(=6^{10}\)
e) \(27^5:81^3\)
\(=\left(3^3\right)^5:\left(3^4\right)^3\)
\(=3^{15}:3^{12}\)
\(=3^{15-12}\)
\(=3^3\)
f) \(10^6:100\)
\(=10^6:10^2\)
\(=10^{6-2}\)
\(=10^4\)
g) \(5^9:25^3\)
\(=5^9:\left(5^2\right)^3\)
\(=5^9:5^6\)
\(=5^{9-6}\)
\(=5^3\)
h) \(4^{10}:64^3\)
\(=4^{10}:\left(4^3\right)^3\)
\(=4^{10-9}\)
\(=4\)
i) \(2^{25}:32^4:18^4:9^4\)
\(=\left(2^{25}:2^{20}\right):\left(18^4\cdot9^4\right)\)
\(=2^5:9^8:2^4\)
\(=2:9^8\)
\(=\dfrac{2}{9^8}\)
\(=\left(3^4\right)^5.\left(2^5\right)^4=3^{20}.2^{20}=6^{20}\)
815+[95+(-815)+(-45)]
\(=\) 815+(95-815-45)
\(=\) 815+95-815-45
\(=\) 50
815+[95+(-815)+(-45)]
= 815 + ( 95 - 815 - 45 )
= 815 + ( - 765 )
= 50
815 + 95 + ( -815) + ( -45)
= [815 + (-815)] + [95 + (-45)]
= 0 + [+(95 - 45)]
= 0 + 50
= 50
= 815 +95 + (-815) + (-45)
= [815+(-815)] +[95 + ( -45)]
=0+50=50
các bạn li-ke mình cho tròn 325 với
815+[95+(-815)+(-45)]= 815+95-815-45=(815-815)+(95-45)=0+50=50
815[95+(-815)+(-45)
=815[-720+(-45)]
=815(-765)
=-623475
mik nha!
Ta có:
\(\frac{10}{11}+\frac{1}{11}=1\) \(\frac{15}{16}+\frac{1}{16}=1\)
\(\frac{12}{13}+\frac{1}{13}=1\)
Vì \(\frac{1}{11}>\frac{1}{13}>\frac{1}{16}\)\(\Rightarrow\frac{10}{11}< \frac{12}{13}< \frac{15}{16}\)
b.
Ta có: \(\frac{-497}{496}>\frac{-497}{815}>\frac{-816}{815}\)
\(\Rightarrow\frac{-497}{496}>\frac{-816}{815}\)
\(\frac{\left(9^{11}.243^5\right)}{\left(81^5.3^{24}\right)}=\frac{9^{11}.\left(3^5\right)^5}{\left(9^2\right)^5.3^{24}}=\frac{9^{11}.3^{25}}{9^{10}.3^{24}}=9.3=27\)
\(\frac{9^3.2^{10}.27^5}{4^5.81^6}=\frac{\left(3^2\right)^3.2^{10}.\left(3^3\right)^5}{\left(2^2\right)^5.\left(3^4\right)^6}=\frac{3^6.2^{10}.3^{15}}{2^{10}.3^{24}}=\frac{3^{21}.2^{10}}{2^{10}.3^{24}}=\frac{1}{3^3}=\frac{1}{27}\)