Question

[Tomatoes]

Tính: 
a) (x - 3y^2)^3
b) (x/2 - y)^3
c) (x/2 + x/3)^3 
d) (2x/3 - 2y)^3

Giúp mik vs!!!

Answer 1

[Kiệt Nguyễn]

a) \(\left(x-3y^2\right)^3=-27y^3+27xy^2-9x^2y+x^3\)

b) \(\left(\frac{x}{2}-y\right)^3=\frac{-8y^3+12xy^2-6x^2y-x^3}{8}\)

c) \(\left(\frac{x}{2}+\frac{x}{3}\right)^3=\frac{\left(5x\right)^3}{6^3}=\left(\frac{5x}{6}\right)^3\)

d) \(\left(\frac{2x}{3}-2y\right)^3=\frac{-216y^3+216xy^2-72x^2y+8x^3}{27}\)