\(\frac{7x+2}{5x+7}=\frac{7x-1}{5x+1}\)là x=...............
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\(\frac{7x+2}{5x+7}=\frac{7x-1}{5x+1}=\frac{7x+2-\left(7x-1\right)}{5x+7-\left(5x+1\right)}=\frac{7x+2-7x+1}{5x+7-5x-1}=\frac{3}{6}=\frac{1}{2}\)
tu \(\frac{7x+2}{5x+7}=\frac{1}{2}=>\left(7x+2\right).2=5x+7=>14x+4=5x+7=>14x-5x=7-4=>9x=3=>x=\frac{3}{9}=\frac{1}{3}\)
vay x=1/3
tick nha
Ta có :
\(\frac{7x+2}{5x+7}=\frac{7x-1}{5x+1}\)
\(=>\left(7x+2\right)\left(5x+1\right)=\left(7x-1\right)\left(5x+7\right)\)
\(=>35x^2+7x+10x+2=35x^2+49x-5x-7\)
\(=>35x^2+17x+2=35x^2+44x-7\)
\(=>17x+2=44x-7\)
\(=>44x-17x=2+7\)
\(=>27x=9\)
\(=>x=\frac{9}{27}=\frac{1}{3}\)
=>(7x+2)*(5x+1)=(5x+7)(7x-1)(t/c 2 p/s bằng nhau)
7x(5x+1)+2(5x+1)=5x(7x-1)+7(7x-1)
35x2+7x+10x+2=35x2-5x+49x-7
17x+2=44x-7
17x-44x=-7-2
-27x=-9
x=-9/-27=1/3
Vậy x=1/3
\(\frac{7x+2}{5x+7}=\frac{7x-1}{5x+1}=\frac{7x+2-7x+1}{5x+7-5x-1}=\frac{3}{6}=\frac{1}{2}\)
2(7x+2) =5x+7
14x -5x = 7 -4
9x =3
=> x =1/3
Có 1 giá trị của x nhé.
\(\frac{7x+2}{5x+7}=\frac{7x-1}{5x+1}=\frac{7x+2-7x+1}{5x+7-5x-1}=\frac{3}{6}=\frac{1}{2}\)
\(2\left(7x+2\right)=5x+7\)
\(14x-5x=7-4\)
\(9x=3\)
\(\Rightarrow x=3\div9\)
\(\Rightarrow x=\frac{1}{3}\)
nhân chéo ta được:
\(\left(7x+2\right)\left(5x+1\right)=\left(5x+7\right)\left(7x-1\right)\)
\(35x^2+7x+10x+2=35x^2-5x+49x-7\) ( nhân phân phối)
\(35x^2-35x^2+7x+10x-5x+49x=-2-7\)
\(-27x=-9\)
\(x=\frac{-9}{-27}\)
\(x=\frac{1}{3}\)
\(x=\frac{1}{3}\)