Thực hiện phép tính
\(\frac{15.12-15}{12-27}\)
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\(\frac{15\cdot12-15}{12-27}=\frac{15\left(12-1\right)}{-15}=\frac{15\cdot11}{-15}=\frac{11}{-1}=-11\)
\(\frac{15.12-15}{12-27}=\frac{15.\left(12-1\right)}{-15}=-1.\left(12-1\right)=-1.11=-11\)\(-11\)
\(\frac{15\times\left(12-1\right)}{-15}=\frac{15\times11}{-15}=\frac{\left(-15\right)\times\left(-11\right)}{-15}=-11\)
Tử số: 2^19 x (3^3)^3 x 5+15 x 4^9 x(3^2)^4
=2^19 x3^9x5 + 15 x(2^2)^9 x 3^8
= 2^19 x 3^9 x 5 +3 x 5 x 2^18 x 3^8
= 2^19 x 3^9 x 5+ 3^9 x 5 x 2^18
= 5 x 3^9 x 2^18 (2+1)
=5 x 3^10 x 2^18
Mẫu số
= (2 x 3)^9 x 2^10 -12^10
= 2^9 x 3^9 x 2^10 - (2^2x3)^10
= 2^9 x 3^9 x 2^10 -2^20 x 3^10
= 2^19 x 3^9 - 2^20 x 3^10
= 2^19 x 3^9 (1-2 x 3)
= 2^19 x 3^9 x(-5)
Chia cả tử và mẫu ta có
(5 x 3^10 x 2^18) / (2^19 x 3^9 x (-5)) = -3/2
\(H=\frac{2^{19}.27^3.5-15.\left(-4\right)^9.9^4}{6^9.2^{10}-\left(-12\right)^{10}}\)
\(\Rightarrow\)\(H=\frac{2^{19}.3^9.5-3.5-1.2^{18}.3^8}{2^9.3^9.2^{10}-6^{10}.2^{10}}=\frac{2^{19}.3^9.5-3^9.5-2^{18}}{2^{19}.3^9-3^{10}.2^{10}.2^{10}}=\frac{2^{19}.3^9.5-3^9.5-2^{18}}{2^{19}.3^9-3^{10}.2^{20}}\)
\(\Rightarrow H=\frac{2^{18}.3^9.5\left(2-1\right)}{2^{19}.3^9.\left(1-3.2\right)}=\frac{5}{2.\left(-5\right)}=\frac{-1}{2}\)
Vậy \(H=\frac{-1}{2}\)
(-12) + (-18)
= -30
------------------
(-90) + 27 + (-10) + 73
= [(-90) + (-10) + (27 + 73)
= -100 + 100
= 0
---------------------------------
25 . (-5) . (-4)
= 25 . (-4) . (-5)
= -100 . (-5)
= 100 . 5
= 500
----------------------------------------
(-15) . 40 : 6
= [(-15) . 40] : 6
= (-600) : 6
= -100
-----------------------------------
(-27) . 58 + (-27) . 42
= (-27) . (58 + 42)
= (-27) . 100
= -2700
\(\frac{11}{15}+\frac{23}{16}-\left(5+\frac{27}{16}-\frac{19}{15}\right)+\left(\frac{-1}{2}\right)^2\)
\(=\frac{11}{15}+\frac{23}{16}-5-\frac{27}{16}+\frac{19}{15}+\frac{1}{4}\)
\(=\left(\frac{11}{15}+\frac{19}{15}\right)+\left(\frac{23}{16}-\frac{27}{16}\right)-5+\frac{1}{4}\)
\(=\frac{30}{15}-\frac{4}{16}-5+\frac{1}{4}\)
\(=2-\frac{1}{4}-5+\frac{1}{4}\)
\(=-3\)
học tốt ngôlãmtân
\(\frac{11}{15}+\frac{23}{16}-\left(5+\frac{27}{16}-\frac{19}{15}\right)+\left(-\frac{1}{2}\right)^2\) = \(\frac{11}{15}+\frac{23}{16}-5-\frac{27}{16}+\frac{19}{15}+\frac{1}{4}\)
\(=2-\frac{1}{4}-5+\frac{1}{4}=2-5=-3\)
Kb với mình nha!
a)\(\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}=\frac{3^6.\left(3^2.5\right)^4-\left(3.5\right)^{13}.5^{-9}}{\left(3^3\right)^4.\left(5^2\right)^3+\left(3^2.5\right)^6}=\frac{3^6.3^8.5^4-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}\)
\(=\frac{3^{14}.5^4-3^{13}.5^4}{3^{12}.5^6+3^{12}.5^6}=\frac{3^{13}.5^4.\left(3-1\right)}{3^{12}.5^6\left(1+1\right)}=\frac{3^{13}.5^4}{3^{12}.5^6}=\frac{3}{5^2}=\frac{3}{25}\)
b)\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}-6^{11}}=\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{-\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{-2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{-2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{-\left(2^{12}.3^{12}+2^{11}.3^{11}\right)}=\frac{2^{12}.3^{10}\left(1+5\right)}{-\left[2^{11}.3^{11}\left(2.3+1\right)\right]}=\frac{2.6}{-\left(3.7\right)}=\frac{4}{-7}\)
\(20\frac{15}{16}.16\frac{8}{9}-20\frac{15}{16}.12\frac{8}{9}\)
\(=20\frac{15}{16}.\left(16\frac{8}{9}-12\frac{8}{9}\right)\)
\(=20\frac{15}{16}.4\)
\(=83\frac{3}{4}\)
a, -72 : (24-27)2+12.(-3)
= -72 : (-3)2+ (-3)
= -72 : 9 + (-3)
= -8 + (-3)
= -11
b,|-15| . (-4)-3 . [(-2)3 -6 *(-8)]
= 15.(-4) - 3 . [(-8) - (-48)]
= -60 - 3 . 40
= -60 - 120
= -180
\(\frac{15\cdot12-15}{12-27}\)
\(=\frac{15\left[12-1\right]}{12-27}\)
\(=\frac{15\cdot11}{12-27}=\frac{3\cdot5\cdot1\cdot11}{3\cdot4-3\cdot9}=\frac{3\cdot5\cdot1\cdot11}{3\left[4-9\right]}=\frac{3\cdot5\cdot1\cdot11}{3\cdot(-5)}=\frac{5\cdot1\cdot11}{-5}=\frac{1\cdot1\cdot11}{-1}=-11\)
15(12-1)/-15=-11