tính:1/2.3+1/2.3.4+1/3.4.5+....+1/8.9.10
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gọi A=................................
=>2A=2/1.2.3+2/2.3.4+.....+2/8.9.10
2A=1/1.2-1/2.3+1/2.3-...+1/8.9-1/9.10
2A=1/1.2-1/9.10=22/45 =>A=11/45
Đặt \(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+\frac{1}{4.5.6}+\frac{1}{5.6.7}+\frac{1}{6.7.8}+\frac{1}{7.8.9}+\frac{1}{8.9.10}\)
\(2A=\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+\frac{2}{4.5.6}+\frac{2}{5.6.7}+\frac{2}{6.7.8}+\frac{2}{7.8.9}+\frac{2}{8.9.10}\)
\(2A=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+\frac{1}{4.5}-\frac{1}{5.6}+...+\frac{1}{8.9}-\frac{1}{9.10}\)
\(2A=\frac{1}{1.2}-\frac{1}{9.10}=\frac{22}{45}\)
\(A=\frac{22}{45}:2=\frac{11}{45}\)
1/ 1.2.3 + 1/ 2.3.4 + 1/ 3.4.5+1/4.5.6+1/5.6.7+1/6.7.8+1/7.8.9+1/8.9.10
= 1 - 1/2 - 1/3 + 1/2 - 1/3 - 1/4 + 1/3 - 1/4 - 1/5 + 1/5 - 1/6 - 1/7 + 1/6 - 1/7 - 1/8 + 1/7 - 1/8 - 1/9 + 1/8 - 1/9 - 1/10
= 1 - 1/10
= 9/10
c, 4C= (1.2.3+2.3.4+3.4.5+...+8.9.10) .4
==> 4C= [1.2.3.(4-0) + 2.3.4-(5-1) + 8.9.10.(11-7)
==>4C= 1.2.3.4 - 1.2.3.4+ 2.3.4.5-2.3.4.5 + 7.8.9.10- 7.8.9.10 + 8.9.10.11
==> 4C= 8.9.10.11=7920
==> C= 7920 :4=1980
a, Ta có: 3A= 1.2.3+2.3.3+3.4.3+...+99.100.3
3A=1.2.(3-0) + 2.3.(4-1)+ 3.4.(5-2)+ ... + 99.100.( 101-98)
3A=(1.2.3 + 2.3.4+ 3.4.5+ 99.100.101) - (0.1.2 +1.2.3+ 2.3.4 + ... + 98.99.100)
3A= 99.100.101 - 0.1.2
3A= 999900 - 0
3A= 999900
==> A= 999900 : 3
==> A= 333300
\(B=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+..+\frac{1}{7.8.9}+\frac{1}{8.9.10}\)
\(B=2\times\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+..+\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)
\(B=2\times\left(1-\frac{1}{10}\right)\)
\(B=2\times\frac{9}{10}\)
\(B=\frac{9}{5}\)
\(B=2\times\left(\frac{1}{1\times2}-\frac{1}{2\times3}+\frac{1}{2\times3}-\frac{1}{3\times4}+\frac{1}{3\times4}-\frac{1}{4\times5}+..+\frac{1}{9\times10}\right)\)
\(B=2\times\left(\frac{1}{1\times2}-\frac{1}{9\times10}\right)\)
\(B=2\times\frac{22}{45}\)
\(B=\frac{44}{45}\)
Đặt A=11.2.3+12.3.4+....+18.9.10A=11.2.3+12.3.4+....+18.9.10
2A=21.2.3+22.3.4+....+28.9.102A=21.2.3+22.3.4+....+28.9.10
=3−11.2.3+4−22.3.4+...+10−88.9.10=3−11.2.3+4−22.3.4+...+10−88.9.10
=11.2−12.3+12.3−13.4+...+18.9−19.10=11.2−12.3+12.3−13.4+...+18.9−19.10
=11.2−19.10=2245=11.2−19.10=2245
A=1145A=1145
Ax=1145x=2245Ax=1145x=2245
x=2245:1145=2
Ta có:
\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{8.9.10}\)
\(=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{90}\right)\)
=\(\frac{11}{45}\)
=1/2.(1/1*2-1/2*3+1/2*3-1/3*4+...+1/8*9-1/9*10)
=1/2.(1/1*2-1/9*10)
=1/2.44/90
=22/90
nha