35+57-57*3:2
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\(35\cdot\left(115-57\right)-115\cdot\left(35-57\right)\)
\(=35\cdot115-35\cdot57-115\cdot35+115\cdot57\)
\(=\) \(-35\cdot57+115\cdot57\)
\(=57\cdot\left(-35+115\right)=57\cdot80=4560\)
\(35.\left(115-57\right)-115.\left(35-57\right)\\ =35.115-35.57-115.35+115.57\\ =\left(35.115-115.35\right)+\left(-35.57+115.57\right)\\ =0+57.\left(-35+115\right)\\ =57.80=4560\)
1: =20*(-4)+24(-30)
=-80-720=-800
2: =-13*57+13*32+57*13-57*45
=13*32-57*45=-2149
3: =-12*8*125
=-12*1000=-12000
4: =(-134)(1-51+48)
=(-134)*(-2)=268
5: =(-24)(45-5)=40*(-24)=-960
2 . 53 . 27 + 6 . 9 . 87 - 3 . 18 . 40
= 2. 53 . 9 . 3 + 2. 3 .9 .87 - 3 .2 .9 .40
= 54.53+54.87-54.40
=54(53+87-40)
=54. 100=5400
12 . 25 + 29 . 25 + 59 . 25
= 25 . ( 12+29+59)
=25 . 90
=2250
43 . 37 + 93 . 43 + 57 . 61 + 69 . 57
= 43.(37+93)+57(61+69)
=43.130+57.130
=130.(43+57)
=130.100
=13 000
12 . 53 + 53 . 172 - 53
=53(12+172-1)
=53.184
=9752
35 . 54 + 35 . 58 + 65 . 75 + 65 . 45
=35(54+58)+65(75+45)
=35.112+65.120
=3920+7800
=11720
39 . 8 + 70 . 3 + 31 . 8
=8(39+31)+70.3
=8.70+70.3
=70.(8+3)
=70.11
=770
\(\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left(\frac{157}{8}:\frac{7}{12}-\frac{53}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left[\left(\frac{157}{8}-\frac{53}{4}\right):\frac{7}{12}\right].\frac{4}{5}\)
\(=\left[\frac{51}{8}:\frac{7}{12}\right].\frac{4}{5}\)
\(=\frac{153}{14}.\frac{4}{5}\)
\(=\frac{306}{35}\)
\(\left(\frac{-2}{5}+\frac{3}{7}\right)-\left(\frac{4}{9}+\frac{12}{20}-\frac{13}{35}\right)+\frac{7}{35}\)
\(=\frac{1}{35}-\frac{212}{315}+\frac{7}{35}\)
\(=\frac{1}{35}+\frac{-212}{315}+\frac{7}{35}\)
\(=\frac{9}{315}+\frac{-212}{315}+\frac{63}{315}\)
\(=\frac{-140}{315}=\frac{-4}{9}\)
\(\dfrac{3}{5}+\dfrac{2}{3}=\dfrac{9}{15}+\dfrac{10}{15}=\dfrac{19}{15}\\ \dfrac{5}{7}-\dfrac{1}{2}=\dfrac{10}{14}-\dfrac{7}{14}=\dfrac{3}{14}\\ \dfrac{5}{6}\times\dfrac{4}{5}=\dfrac{1}{3}\times\dfrac{2}{1}=\dfrac{2}{3}\\ \dfrac{7}{9}:\dfrac{4}{3}=\dfrac{7}{9}\times\dfrac{3}{4}=\dfrac{7}{12}\)
\(\dfrac{3}{5}+\dfrac{2}{3}=\dfrac{9}{15}+\dfrac{10}{15}=\dfrac{19}{15}\)
\(\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{10}{14}-\dfrac{7}{14}=\dfrac{3}{14}\)
\(\dfrac{5}{6}\text{×}\dfrac{4}{5}=\dfrac{5\text{×}4}{6\text{×}5}=\dfrac{2}{3}\)
\(\dfrac{7}{9}:\dfrac{4}{3}=\dfrac{7}{9}\text{×}\dfrac{3}{4}=\dfrac{7\text{×}3}{9\text{×}4}=\dfrac{7\text{×}3}{3\text{×}3\text{×}4}=\dfrac{7}{12}\)
A = 1 3 − 1 3 + 3 5 − 3 5 + 5 7 − 5 7 + 7 9 − 7 9 + 9 11 − 9 11 + 11 13 − 11 13 + 13 15 = > A = 13 15 .
a) (-30) + 17 + (-70) + 33
=[-30+(-70)]+(17+33)
=-100+50
=-50
b) 56 - 15 - 6 + (-75)
=(56-6)-[15+(-75)]
=50-(-60)
=110
c) (157 - 56) - (44 + 57)
=157-56-44+57
=(-157-57)-(56+44)
=-100-100
=-200
d) (-24 + 174) - (174 - 24)
=-24+174-174+24
=(-24+24)+(174-174)
=0+0
=0
e) (35 - 47) - (-123 + 35) + [20 - (123 - 57)]
=35-47+123-35+[20-123+57]
=35-47+123-35+20-123+57
=(35-35)+(123-123)+(-47+57)
=0+0+(-10)
=-10
TK
a) (35 - 15).(-4) + 24.(-13 - 17)
= 20.(-4) + 24.(-30)
= (-80) + (-720)
b) (-13).(57 - 34) +57. (13 - 45)
= (-13).23 + 57.(-32)
= (-299) + (-1824)
= -2123
35+57-57*3:2=35+57-171:2=35+57-85,5=92-85,5=6,5
35+57-57*3:2
=35+57-171:2
=35+57-85,5
=92-85,5
=6,5
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