tính: L =\(\dfrac{\left(\dfrac{13}{84}.1,4-2,5.\dfrac{7}{180}\right):2\dfrac{7}{18}+4\dfrac{1}{2}.0,1}{70,5-528:7\dfrac{1}{2}}\)
K
Khách
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KL
15 tháng 8 2017
a, (3\(\dfrac{1}{5}-2\dfrac{1}{3}+\dfrac{5}{6}\)) - (1,5 - \(\dfrac{2}{3}+\dfrac{1}{6}\))
= \(\dfrac{16}{5}-\dfrac{7}{3}+\dfrac{5}{6}-\dfrac{3}{2}+\dfrac{2}{3}-\dfrac{1}{6}\)
= (\(\dfrac{16}{5}-\dfrac{3}{2}\)) - (\(\dfrac{7}{3}-\dfrac{2}{3}\)) + (\(\dfrac{5}{6}-\dfrac{1}{6}\))
= \(\dfrac{17}{10}-\dfrac{5}{3}+\dfrac{2}{3}\)
= \(\dfrac{17}{10}-1\)
= \(\dfrac{7}{10}\)
@Christina
KL
15 tháng 8 2017
b, \(\dfrac{\left(3\dfrac{1}{5}.1,4-2,5.\dfrac{7}{108}\right):2\dfrac{7}{18}+4\dfrac{1}{2}.0,1}{70,5-5,28:7\dfrac{1}{2}}\)
= \(\dfrac{\left(\dfrac{16}{5}.\dfrac{7}{5}-\dfrac{5}{2}.\dfrac{7}{108}\right):\dfrac{43}{18}+\dfrac{9}{2}.\dfrac{1}{10}}{\dfrac{141}{2}-\dfrac{132}{25}:\dfrac{15}{2}}\)
= \(\dfrac{\left(\dfrac{112}{25}-\dfrac{35}{216}\right):\dfrac{43}{18}+\dfrac{9}{20}}{\dfrac{141}{2}-\dfrac{88}{125}}\)
= \(\dfrac{\dfrac{112}{25}:\dfrac{43}{18}-\dfrac{25}{216}:\dfrac{43}{18}+\dfrac{9}{20}}{\dfrac{17449}{250}}\)
= \(\dfrac{\dfrac{2016}{1075}-\dfrac{25}{516}+\dfrac{9}{20}}{\dfrac{17449}{250}}\)
= \(\dfrac{\dfrac{2016}{1075}+\dfrac{259}{645}}{\dfrac{17449}{250}}\)
= \(\dfrac{\dfrac{7343}{3225}}{\dfrac{17449}{250}}\)
@Christina
Q
11 tháng 4 2017
a) \(\dfrac{1}{2}.\left(\dfrac{2}{9}+\dfrac{3}{7}-\dfrac{5}{27}\right)\)
\(=\dfrac{1}{2}.\left(\dfrac{41}{63}-\dfrac{5}{27}\right)\)
\(=\dfrac{1}{2}.\dfrac{88}{189}\)
\(=\dfrac{44}{189}\)
b) \(\left(\dfrac{-5}{28}+1,75+\dfrac{8}{35}\right):\left(-3\dfrac{9}{20}\right)\)
\(=\left(\dfrac{11}{7}+\dfrac{8}{35}\right):\left(-3\dfrac{9}{20}\right)\)
\(=\dfrac{9}{5}:\left(-3\dfrac{9}{20}\right)\)
\(=\dfrac{9}{5}:\dfrac{-69}{20}\)
\(=\dfrac{-12}{23}\)
c) \(\dfrac{1}{3}.\dfrac{5}{7}-\dfrac{7}{27}.\dfrac{36}{14}\)
\(=\dfrac{5}{21}-\dfrac{7}{27}.\dfrac{36}{14}\)
\(=\dfrac{5}{21}-\dfrac{2}{3}\)
\(=\dfrac{-3}{7}\)
d) \(70,5-528:\dfrac{15}{2}\)
\(=70,5-\dfrac{352}{5}\)
\(=\dfrac{1}{10}\)
11 tháng 4 2017
em không trả lời được câu hỏi của chị nhưng chị có thể giúp em đăng bài toán lên bằng cách nào không
H
23 tháng 8 2023
\(=\left(-\dfrac{3}{4}+\dfrac{5}{13}\right).\dfrac{7}{2}-\left(\dfrac{9}{4}+\dfrac{8}{13}\right).\dfrac{7}{2}\\ =\dfrac{7}{2}\left(-\dfrac{3}{4}+\dfrac{5}{13}-\dfrac{9}{4}-\dfrac{8}{13}\right)\\ =\dfrac{7}{2}\left(-\dfrac{12}{4}-\dfrac{3}{13}\right)\\ =\dfrac{7}{2}\left(-3-\dfrac{3}{13}\right)\\ =\dfrac{7}{2}\left(-\dfrac{39}{13}-\dfrac{3}{13}\right)\\ =\dfrac{7}{2}\left(-\dfrac{42}{13}\right)\\ =\dfrac{7.\left(-42\right)}{2.13}\\ =-\dfrac{147}{13}\)
29 tháng 3
a)\(\dfrac{-10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)
=\(\dfrac{10}{11}.\dfrac{-8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)
=\(\dfrac{10}{11}(\dfrac{-8}{9}+\dfrac{7}{18})\)
=\(\dfrac{10}{11}.\dfrac{-1}{2}\)
=\(\dfrac{-5}{11}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
7 tháng 8
b;
B = \(\dfrac{3}{14}\) : \(\dfrac{1}{28}\) - \(\dfrac{13}{21}\): \(\dfrac{1}{28}\) + \(\dfrac{29}{42}\) : \(\dfrac{1}{28}\) - 8
B = (\(\dfrac{3}{14}\) - \(\dfrac{13}{21}\) + \(\dfrac{29}{42}\)) - 8
B = (\(\dfrac{9}{42}\) - \(\dfrac{26}{42}\) + \(\dfrac{29}{42}\)) - 8
B = (\(\dfrac{-17}{42}\) + \(\dfrac{29}{42}\)) - 8
B = \(\dfrac{2}{7}\) - 8
B = \(\dfrac{2}{7}-\dfrac{56}{7}\)
B = - \(\dfrac{54}{7}\)
BN
11 tháng 3 2022
1) âm năm phần 12
2) âm mười bảy phần 9
3) -1
Đây là đáp án còn làm bài từ làm nhé
11 tháng 4 2017
a )
\(\frac{2}{7}+\frac{7}{7}.\frac{14}{25}\)
\(=\frac{2}{7}+1.\frac{14}{25}=\frac{2}{7}+\frac{14}{25}\)
\(=\frac{50}{175}+\frac{98}{175}=\frac{148}{175}\)
b)
\(\frac{6}{7}+\frac{5}{7}:5-\frac{8}{9}\)
\(=\frac{6}{7}+\frac{5}{30}-\frac{8}{9}\)
\(=\frac{6}{7}+\frac{1}{6}-\frac{8}{9}\)
\(=\frac{36}{42}+\frac{7}{42}-\frac{8}{9}\)
\(=\frac{43}{42}-\frac{8}{9}=\frac{129}{126}-\frac{112}{126}=\frac{17}{126}\)
tk ủng hộ mk nha!!!!!!!!
\(=\dfrac{\left(\dfrac{13}{84}\cdot\dfrac{7}{5}-\dfrac{5}{2}\cdot\dfrac{7}{180}\right):\dfrac{43}{18}+\dfrac{9}{2}\cdot\dfrac{1}{10}}{70.5-528:7.5}\)
\(=\dfrac{\left(\dfrac{13}{60}-\dfrac{7}{72}\right)\cdot\dfrac{18}{43}+\dfrac{9}{20}}{0.1}\)
\(=10\cdot\left[\dfrac{43}{360}\cdot\dfrac{18}{43}+\dfrac{9}{20}\right]\)
\(=10\cdot\left[\dfrac{1}{20}+\dfrac{9}{20}\right]=10\cdot\dfrac{10}{20}=5\)