Question

[nguyễn hà ngọc hân]

\(\dfrac{x}{y}=\dfrac{17}{3}vàx+y=-60\)

Answer 1

[Nguyễn Mai Phương]

sorry mik nhầm ở phần áp dụng :

\(\dfrac{x}{17}=\dfrac{y}{3}=\dfrac{x+y}{17+3}=\dfrac{-60}{20}=-3\) ( do x + y = -60 )

+) \(\dfrac{x}{17}=-3\Rightarrow x=-3.17=-51\)

+) \(\dfrac{y}{3}=-3\Rightarrow y=-3.3=-9\)

Vậy x = -51 , y = -9

Answer 2

[Akai Haruma]

Lời giải:

\(\frac{x}{y}=\frac{17}{3}\Rightarrow \frac{x}{y}+1=\frac{17}{3}+1\)

\(\Rightarrow \frac{x+y}{y}=\frac{20}{3}\)

Thay \(x+y=-60\) ta có: \(\frac{-60}{y}=\frac{20}{3}\Rightarrow y=\frac{-60.3}{20}=-9\)

\(\Rightarrow x=-60-y=-60-(-9)=-51\)

Vậy \((x,y)=(-51, -9)\)