1.2.3+2.3.4+...........+98.99.100
ghi lời giải rõ ràng nhé
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\(D=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\frac{1}{3\cdot4\cdot5}+...+\frac{1}{10\cdot11\cdot12}\)
\(D=\frac{1}{2}\left(\frac{2}{1\cdot2\cdot3}+\frac{2}{2\cdot3\cdot4}+\frac{2}{3\cdot4\cdot5}+...+\frac{2}{10\cdot11\cdot12}\right)\)
\(D=\frac{1}{2}\left(\frac{1}{1\cdot2}-\frac{1}{2\cdot3}+\frac{1}{2\cdot3}-\frac{1}{3\cdot4}+\frac{1}{3\cdot4}-\frac{1}{4\cdot5}+...+\frac{1}{10\cdot11}-\frac{1}{11\cdot12}\right)\)
\(D=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{132}\right)=...\)
\(D=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{10.11.12}\)
\(D=\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{10.11.12}\right).\frac{1}{2}\)
\(D=\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{10.11}-\frac{1}{11.12}\right).\frac{1}{2}\)
\(D=\left(\frac{1}{1.2}-\frac{1}{11.12}\right).\frac{1}{2}\)
\(D=\frac{65}{132}.\frac{1}{2}\)
\(D=\frac{65}{264}\)
I don't now
mik ko biết
sorry
......................
b,\(B=2^2+4^2+...+20^2\)
\(\Rightarrow B=2^2\left(1^2+2^2+...+10^2\right)\)
\(\Rightarrow B=4.\left[1.\left(2-1\right)+2.\left(3-1\right)+...+10.\left(11-1\right)\right]\)
\(\Rightarrow B=4\left(1.2-1+2.3-2+...+10.11-10\right)\)
\(\Rightarrow B=4\left[\left(1.2+2.3+...+10.11\right)-\left(1+2+...+10\right)\right]\)
\(\Rightarrow B=4\left(\frac{10.11.12}{3}-\frac{11.10}{2}\right)\)
25 x 2 + 25 x 3 + 25 x 4 + 25
= 25 x (2 + 3 + 4 + 1)
= 25 x 10
= 250
**** cho mình nhé >_<
25x2+25x3+25x4+25
= 25 × 2 + 25 × 3 + 25 × 4 + 25 × 1
= 25 × ( 2 + 3 + 4 + 1 )
= 25 × 10
= 250
Nếu mình đúng thì các bạn k mình nhé
Ta có : \(\frac{5}{7}=\frac{x}{63}\)
\(\Rightarrow\) \(\frac{45}{63}=\frac{x}{63}\)
\(\Rightarrow\) \(x=45\)
Vậy x = 45
Cbht !!! ❤️❤️❤️
\(\frac{5}{7}=\frac{x}{63}\\ \Leftrightarrow5\times63=7x.\)
\(\Leftrightarrow315=7x\)
\(\Leftrightarrow x=45\)