Question

[Awsam My]

(x-1)^x+2=(x-1)^x+6 ( x thuộc Z )

nhanh nha mk đang cần gấp

Answer 1

[Incursion_03]

\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+6}\)

\(\Leftrightarrow\left(x-1\right)^{x+6}-\left(x-1\right)^{x+2}=0\)

\(\Leftrightarrow\left(x-1\right)^{x+2}\left[\left(x-1\right)^4-1\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}\left(x-1\right)^{x+2}=0\\\left(x-1\right)^4=1\end{cases}}\)

\(\Leftrightarrow x-1=0\left(h\right)x-1=1\left(h\right)x-1=-1\)

\(\Leftrightarrow x=1\left(h\right)x=2\left(h\right)x=0\)

Vậy \(x\in\left\{0;1;2\right\}\)

Answer 2

[Awsam My]

(h) là j vậy bạn