2^5.3^2+2^5.11-2^6.5-5 (tính nhanh)
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\(\frac{2^5.3^6+6^5.11}{12^5-6^5.2^2}\)
\(=\frac{2^5.3^6+2^5.3^5.11}{2^2.3-2^5.3^5.2^2}\)
\(=\frac{2^5.3^5.\left(3+11\right)}{2^2.3\left(1-2^5.3^4\right)}\)
\(=\frac{2^3.3^4.14}{1-32.81}\)
\(=\frac{2^4.3^4.7}{-2591}\)
\(\frac{2^5\cdot3^6+6^5\cdot11}{12^5-6^5.2^2}\)
\(=\frac{6^5\cdot3+6^5\cdot11}{6^5\cdot2^5-6^5\cdot2^2}\)
\(=\frac{6^5\cdot\left(3+11\right)}{6^5\cdot\left(2^5-2^2\right)}\)
\(=\frac{14}{32-4}\)
\(=\frac{14}{28}=\frac{1}{2}\)
\(=\frac{2^5.3^5.2^2.5^2}{2^5.3^6.5}=\frac{5.2^2}{3}=\frac{20}{3}\)
3/5 . 11/7 + 3/5 . (- 4/7) + 2/5
= 3/5 . [11/7 + (- 4/7)] + 2/5
= 3/5 . 1 + 2/5
= 3/5 + 2/5
= 1
a) 5.3x = 405
3x = 81 = 34
=> x = 4
b) 2x : 8 = 4
2x = 32 = 25
=> x = 5
c) x64 = x
=> x64 - x = 0
x.(x63 -1) = 0
=> x = 0
x63 - 1 = 0 => x63 = 1 => x = 1
KL: ...
phần d lm tương tự phần c nha bn
e) (x-2)5 = 243 = 35
=> x - 2 = 3
x = 5
g) (x+1)3 = 125 = 53
=> x + 1 = 5
x = 4
\(\frac{2^5.7+2^5}{2^5+5^2-2^5.3}\)
\(=\frac{2^5.8}{5^2.3}\)
\(=\frac{32.8}{25.3}\)
\(=\frac{256}{75}\)