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\(=\frac{2^5.3^5.2^2.5^2}{2^5.3^6.5}=\frac{5.2^2}{3}=\frac{20}{3}\)
1;Ta có\(5.3^x=5.3^4\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
2.Ta có \(9.5^x=6.5^6+3.5^6\)
\(\Rightarrow9.5^x=5^6.\left(6+3\right)\)
\(\Rightarrow9.5^x=9.5^6\)
\(\Rightarrow5^x=5^6\)\
\(\Rightarrow x=6\)
3, Ta có \(2.3^{x+2}+4.3^{x+1}=10.3^6\)
\(\Rightarrow3^{x+1}.\left(2.3+4\right)=10.3^6\)
\(\Rightarrow3^{x+1}.10=10.3^6\)
\(\Rightarrow3^{x+1}=3^6\)
\(\Rightarrow x+1=6\)
\(\Rightarrow x=5\)
a) 5.3x = 5.34
=> 3x=34
=> x=4
b) 9.5x=6.56+3.56
=> 9.5x = (6+3)56
=> 9.5x=9.56
=> 5x=56
=> x=6
c) 2.3x+2 + 4.3x+1 = 10.36
=> 2.3x+1.3 + 4.3x+1 = 10.36
=> 6.3x+1+4.3x+1=10.36
=> (6+4).3x+1=10.36
=> 10.3x+1=10.36
=> 3x+1=36
=> x+1=6
=> x=5
\(\frac{3^{10}+6^2}{5\cdot3^8+20}\)
\(=\frac{3^{10}+\left(3 \cdot2\right)^2}{5\cdot3^8+5\cdot4}\)
\(=\frac{3^{10}+3^2\cdot2^2}{5\cdot\left(3^8+4\right)}\)
\(=\frac{3^2\cdot\left(3^8+2^2\right)}{5\cdot\left(3^8+4\right)}\)
\(=\frac{3^2\cdot\left(3^8+4\right)}{5\cdot\left(3^8+4\right)}\)
\(=\frac{3^2}{5}\)
\(=\frac{9}{5}\)
\(\frac{2^5.3^6+6^5.11}{12^5-6^5.2^2}\)
\(=\frac{2^5.3^6+2^5.3^5.11}{2^2.3-2^5.3^5.2^2}\)
\(=\frac{2^5.3^5.\left(3+11\right)}{2^2.3\left(1-2^5.3^4\right)}\)
\(=\frac{2^3.3^4.14}{1-32.81}\)
\(=\frac{2^4.3^4.7}{-2591}\)
\(\frac{2^5\cdot3^6+6^5\cdot11}{12^5-6^5.2^2}\)
\(=\frac{6^5\cdot3+6^5\cdot11}{6^5\cdot2^5-6^5\cdot2^2}\)
\(=\frac{6^5\cdot\left(3+11\right)}{6^5\cdot\left(2^5-2^2\right)}\)
\(=\frac{14}{32-4}\)
\(=\frac{14}{28}=\frac{1}{2}\)
\(\frac{3^{10}+6^2}{5.3^8+20}=\frac{3^2+6^2}{5+20}=\frac{9^2}{25}=\frac{81}{25}=\frac{9}{5}\)