A=\(\frac{1}{\sqrt{x}}+\frac{\sqrt{x}}{\sqrt{x}+1}\)=\(\frac{x+\sqrt{x}+1}{\sqrt{x}\left(\sqrt{x}+1\right)}\)(đk1:x>0)
B=\(\frac{\sqrt{x}}{\sqrt{x}+x}\)=\(\frac{1}{\sqrt{x}+1}\)(đk2:x>0)
a)đặt P=A:B. Tìm x thoả mãn \(P\sqrt{x}+\left(2\sqrt{x}-1\right).\sqrt{x}=3x-2\sqrt{x-4}+3\)
ai làm xong trước mình cho 1 like :)))