\(\frac{3^2.3^8}{27^3}=3^x\)
Tìm x
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24 tháng 10 2015
\(\frac{3^2.3^8}{\left(3^3\right)^3}=3^x\frac{3^{10}}{3^9}=3^x3^{10-9}=3^x3^x=3x=1\)
XO
17 tháng 11 2019
Ta có :\(\frac{3^2.3^8}{27^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{\left(3^3\right)^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{3^9}=3^x\)
\(\Rightarrow3^1=3^x\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
1 tháng 10 2016
\(\frac{3^2.3^8}{37^3}=3^x\)
\(\Rightarrow\frac{3^{10}}{\left(3^3\right)^3}=3^x\Rightarrow\frac{3^{10}}{3^9}=3^x\Rightarrow3^1=3^x\Rightarrow x=1\)
CG
1
A
16 tháng 11 2023
a)
\(\text{( 25 – 2x )³ : 5 – 3^2 = 4^2}\)
\(\text{( 25 – 2x )³ : 5 – 9 = 16}\)
\(\text{( 25 – 2x )³ : 5 = 16 + 9}\)
\(\text{( 25 – 2x )³ : 5 = 25}\)
\(\text{( 25 – 2x )³ = 25 . 5}\)
\(\text{( 25 – 2x )³ = 125}\)
\(\text{( 25 – 2x )³ = 5³}\)
\(\text{25 – 2x = 5}\)
\(\text{2x = 25 – 5}\)
\(\text{2x = 20}\)
\(\text{x = 10}\)
\(\text{________________________________________}\)
b)
\(\text{2.3^x = 10.3^12 + 8.27^4}\)
\(\text{2.3^x = 10.3^12 + 8.(3^3)^4}\)
\(\text{2.3^x = 3^12 . (10+8)}\)
\(\text{2.3^x = 3^12 . 18}\)
\(\text{3^x = 3^12 . 18:2}\)
\(\text{3^x = 3^12 . 9}\)
\(\text{3^x = 3^12 . 3^2}\)
\(\text{3^x = 3^14}\)
\(\text{=> x=14}\)
TN
Mọi người giúp mình bài tìm x
1) (x-2/9)^3 = (8/27)^2
2)2.3^x -405 = 3^x-1
3)4/3 : 0,8 = 0,75x : (-1,5)
0
TN
Mọi người giúp mình bài tìm x
1) (x-2/9)^3 = (8/27)^2
2)2.3^x -405 = 3^x-1
3)4/3 : 0,8 = 0,75x : (-1,5)
0
TN
Mọi người giúp mình bài tìm x
1) (x-2/9)^3 = (8/27)^2
2)2.3^x -405 = 3^x-1
3)4/3 : 0,8 = 0,75x : (-1,5)
0
29 tháng 11 2016
a)\(\left(-3\right)^{x+3}=-\frac{1}{27}\)
\(\left(-3\right)^{x+3}=\left(-\frac{1}{3}\right)^3\)
\(\left(-3\right)^{x+3}=\left(-\frac{3^0}{3^1}\right)^3\)
\(\left(-3\right)^{x+3}=\left(-3^{-1}\right)^3\)
\(\left(-3\right)^{x+3}=\left(-3\right)^{-3}\)
\(\Rightarrow x+3=-3\)
\(\Rightarrow x=-6\)
b)\(\left(-6\right)^{2x+2}=\frac{1}{36}\)
\(\left(-6\right)^{2x+2}=\left(-\frac{1}{6}\right)^2\)
\(\left(-6\right)^{2x+2}=\left(-\frac{6^0}{6^1}\right)^2\)
\(\left(-6\right)^{2x+2}=\left(-6^{-1}\right)^2\)
\(\left(-6\right)^{2x+2}=\left(-6\right)^{-2}\)
\(\Rightarrow2x+2=-2\)
\(\Rightarrow2x=-4\)
\(\Rightarrow x=-2\)
c)\(\left(-3\right)^{x+5}=\frac{1}{81}\)
\(\left(-3\right)^{x+5}=\left(-\frac{1}{3}\right)^4\)
\(\left(-3\right)^{x+5}=\left(-\frac{3^0}{3^1}\right)^4\)
\(\left(-3\right)^{x+5}=\left(-3^{-1}\right)^4\)
\(\left(-3\right)^{x+5}=\left(-3\right)^{-4}\)
\(\Rightarrow x+5=-4\)
\(\Rightarrow x=-9\)
29 tháng 11 2016
d)\(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^6\)
\(\left[\left(\frac{1}{3}\right)^2\right]^x=\left[\left(\frac{1}{3}\right)^3\right]^6\)
\(\left(\frac{1}{3}\right)^{2x}=\left(\frac{1}{3}\right)^{18}\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=9\)
e)\(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)
\(\left[\left(\frac{2}{3}\right)^2\right]^x=\left[\left(\frac{2}{3}\right)^3\right]^6\)
\(\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{18}\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=9\)
\(\frac{3^2.3^8}{27^3}=3^x\)
\(\Leftrightarrow\frac{3^{2+8}}{\left(3^3\right)^3}=3^x\)
\(\Leftrightarrow\frac{3^{10}}{3^9}=3^x\)
\(\Leftrightarrow3=3^x\)
\(\Leftrightarrow x=1\)
\(\frac{3^2.3^8}{27^3}=3^x\)
<=> \(\frac{3^{10}}{3^9}=3^x\)
<=> \(3=3^x\)
<=> x=1