Tính:
a)\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{99^2}-1\right)\))
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KB
26 tháng 3 2019
1, A=\(\frac{3}{2}.\frac{4}{3}.\frac{5}{4}....\frac{100}{99}\)
A= \(\frac{100}{2}\)
A=50
2, B=\(\frac{-1}{2}.\frac{-2}{3}....\frac{-98}{99}\)
B= \(\frac{1}{99}\)
HN
26 tháng 3 2019
\(A=\left(\frac{1}{2}+1\right)\cdot\left(\frac{1}{3}+1\right)\cdot\left(\frac{1}{4}+1\right)......\left(\frac{1}{99}+1\right)\)
\(=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}......\frac{99}{98}\cdot\frac{100}{99}\)
\(=\frac{100}{2}\)
\(=50\)
\(B=\left(\frac{1}{2}-1\right)\cdot\left(\frac{1}{3}-1\right)\cdot\left(\frac{1}{4}-1\right)......\left(\frac{1}{99}-1\right)\)
\(=\left(-\frac{1}{2}\right)\cdot\left(-\frac{2}{3}\right)\cdot\left(-\frac{3}{4}\right).....\left(-\frac{97}{98}\right)\cdot\left(-\frac{98}{99}\right)\)
\(=-\frac{1}{99}\)
28 tháng 12 2019
\(=\frac{1-2^2}{2^2}.\frac{1-3^2}{3^2}.\frac{1-4^2}{4^2}...\frac{1-98^2}{98^2}.\frac{1-99^2}{99^2}\)
\(=\frac{2^2-1}{2^2}.\frac{3^2-1}{3^2}.\frac{4^2-1}{4^2}...\frac{98^2-1}{98^2}.\frac{99^2-1}{99^2}\)
= \(\frac{\left(2-1\right).\left(2+1\right)}{2^2}.\frac{\left(3-1\right).\left(3+1\right)}{3^2}.\frac{\left(4-1\right).\left(4+1\right)}{4^2}...\frac{\left(98-1\right)\left(98+1\right)}{98^2}.\frac{\left(99-1\right)\left(99+1\right)}{99^2}\)
\(=\frac{\left(2-1\right).\left(3-1\right).\left(4-1\right)...\left(99-1\right)}{2.3.4...98.99}.\frac{\left(2+1\right).\left(3+1\right).\left(4+1\right)...\left(99+1\right)}{2.3.4...98.99}\)
\(=\frac{1.2.3....98}{2.3.4...98.99}.\frac{3.4.5...100}{2.3.4...98.99}\)
\(=\frac{1}{99}.\frac{100}{2}\)
\(=\frac{50}{99}\)
Chúc bạn học tốt !!!
29 tháng 3 2017
a) \(=\frac{3}{2}.\frac{4}{3}....\frac{100}{99}=\frac{100}{2}=50\)
29 tháng 3 2017
a) =3/2 . 4/3 . 5/4 ...100/99
=\(\frac{3.4.5...100}{2.3.4..99}\)
=\(\frac{100}{2}\)
b) =
\(=-\left(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{9800}{9801}\right)\)
\(=-\left(\frac{1.3}{2.2}.\frac{2.4}{3.3}...\frac{98.100}{99.99}\right)\)
\(=-\left(\frac{1.2.3....98}{2.3...99}.\frac{3.4.5...100}{2.3...99}\right)\)
\(=-\left(\frac{1}{99}.50\right)\)
\(=-\frac{50}{99}\)
Chúc hok tốt!!!
\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\left(\frac{1}{99^2}-1\right)\)
= \(\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}...\frac{98.100}{99.99}\)
= \(\frac{\left(1.2.3...98\right).\left(3.4.5...100\right)}{\left(2.3.4...99\right).\left(2.3.4...99\right)}\)
= \(\frac{100}{99.2}\)= \(\frac{50}{99}\)