Tìm x khi:
17/6 - (x - 7/6 ) = 7/4
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\(\frac{17}{6}-\left(x-\frac{7}{6}\right)=\frac{7}{4}\)
\(x-\frac{7}{6}=\frac{13}{12}\)
\(x=\frac{9}{4}\)
17/6 - ( x - 7/6 ) = 7/4
( x - 7/6 ) = 17/6 - 7/4
( x - 7/6 ) = 13/12
x = 13/12 + 7/6
x = 9/4
\(-\frac{4}{9}+\left(-\frac{5}{6}\right)-\frac{17}{4}=-\frac{199}{36}\)
\(-x-\frac{2}{3}=-\frac{6}{7}\)
\(\Rightarrow-x=-\frac{6}{7}+\frac{2}{3}\)
\(\Rightarrow-x=-\frac{4}{21}\)
\(\Rightarrow x=\frac{4}{21}\)
\(\frac{4}{7}-x=\frac{1}{3}\)
\(\Rightarrow x=\frac{4}{7}-\frac{1}{3}\)
\(\Rightarrow x=\frac{5}{21}\)
1. -4/9 + ( -5/6) -17/4
= -23/18 - 17/4 = -199/36
2.tìm x
a. -x - 2/3 = -6/7
-x = -6/7 +2/3
-x = -4/21
x=4/21
b. 4/7 - x = 1/3
x = 4/7 - 1/3
x =5/21
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
Bài 1:
a) Ta có: \(\dfrac{17}{6}-x\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)
\(\Leftrightarrow\dfrac{17}{6}-x^2+\dfrac{7}{6}x-\dfrac{7}{4}=0\)
\(\Leftrightarrow-x^2+\dfrac{7}{6}x+\dfrac{13}{12}=0\)
\(\Leftrightarrow-12x^2+14x+13=0\)
\(\Delta=14^2-4\cdot\left(-12\right)\cdot13=196+624=820\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{14-2\sqrt{205}}{-24}=\dfrac{-7+\sqrt{205}}{12}\\x_2=\dfrac{14+2\sqrt{2015}}{-24}=\dfrac{-7-\sqrt{205}}{12}\end{matrix}\right.\)
b) Ta có: \(\dfrac{3}{35}-\left(\dfrac{3}{5}-x\right)=\dfrac{2}{7}\)
\(\Leftrightarrow\dfrac{3}{5}-x=\dfrac{3}{35}-\dfrac{10}{35}=\dfrac{-7}{35}=\dfrac{-1}{5}\)
hay \(x=\dfrac{3}{5}-\dfrac{-1}{5}=\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)
a) \(435-\left(x+16\right)=425:17\)
\(435-\left(x+16\right)=25\)
\(x+16=435-25\)
\(x+16=410\)
\(x=410-16\)
\(x=394\)
b) \(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)
\(x+\frac{3}{4}=\frac{23}{6}:\frac{7}{4}\)
\(x+\frac{3}{4}=\frac{46}{21}\)
\(x=\frac{46}{21}-\frac{3}{4}\)
\(x=\frac{121}{84}\)
435 - ( x + 16 ) = 425 : 17
435 - ( x + 16 ) = 25
x + 16 = 435 - 25
x + 16 = 410
x = 410 - 16
x = 394
\(\dfrac{17}{6}-\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)
\(\Leftrightarrow\dfrac{17}{6}-x-\dfrac{7}{6}=\dfrac{7}{4}\)
\(\Leftrightarrow\left(\dfrac{17}{6}-\dfrac{7}{6}\right)-x=\dfrac{7}{4}\)
\(\Leftrightarrow\dfrac{5}{3}-x=\dfrac{7}{4}\)
\(\Leftrightarrow x=-\dfrac{1}{12}\)
Vậy ...
vi diệu :)