(3x-2)^5=-243
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![](https://rs.olm.vn/images/avt/0.png?1311)
(3x-2)5 = -243
<=> (3x-2)5 = (-5)5
<=> 3x-2= -5
<=> 3x =-5+2=-3
<=> x= -1
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có : -243 = (-3)^5
=> 3x -2 =-3
<=>3x =-3 +2
<=>3x = -1 ( âm một)
<=>x = -1÷3
=> x=-1/3
Vậy x=-1/3
![](https://rs.olm.vn/images/avt/0.png?1311)
(3x - 2)5 = -243
=> (3x - 2)5 = (-3)5
=> 3x - 2 = -3
=> 3x = -1
=> x = -1/3
![](https://rs.olm.vn/images/avt/0.png?1311)
( 3x - 2 ) ^ 5 = ( -3 )^ 5
<=> 3x - 2 = -3
<=> 3x = -3 + 2
<=> 3x = -1
<=> x = -1 / 3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-2\right)^5=243\)
\(\left(3x-2\right)^5=3^5\)
\(\Rightarrow3x-2=3\)
\(\Rightarrow3x=5\)
\(\Rightarrow x=\frac{5}{3}\)
vậy \(x=\frac{5}{3}\)
tiểu thư song ngư học tốt
( 3x - 2 )5 = 243
( 3x -2 )5 = 35
=> 3x - 2 = 3
=> 3x = 5
=> x = 5/3
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(2x-1\right)^5=243\)
\(\left(2x-1\right)^5=3^5\)
\(\Rightarrow2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=\frac{4}{2}\)
\(x=2\)
Vậy .......
b) \(\left(3x+2\right)^3=125\)
\(\left(3x+2\right)^3=5^3\)
\(\Rightarrow3x+2=5\)
\(3x=5-2\)
\(3x=3\)
\(x=\frac{3}{3}=1\)
Vậy ..........
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-2\right)^5=-243\)
\(\Leftrightarrow\left(3x-2\right)^5=-3^5\)
\(\Leftrightarrow3x-2=-3\)
\(\Leftrightarrow3x=-1\)
\(\Leftrightarrow x=-\frac{1}{3}\)
\(\left(3x-2\right)^5=-243\)
\(\Leftrightarrow\left(3x-2\right)^2=\left(-3\right)^5\)
\(\Rightarrow3x-2=-3\)
\(\Rightarrow3x=-3+2\)
\(\Rightarrow3x=-1\)
\(\Rightarrow x=-\frac{1}{3}\)
\(\left(3x-2\right)^5=-243\)
\(\left(3x-2\right)^5=-3^5\)
\(3x-2=-3\)
\(3x=-3+2\)
\(3x=-1\)
\(x=\dfrac{-1}{3}\)
Vậy \(x=\dfrac{-1}{3}\)
(3x -2)5 = -243
(3x -2)5 = (-3)5
3x-2 =-3
3x =-1
x =\(\dfrac{-1}{3}\)
Vậy x=\(\dfrac{-1}{3}\)
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