2016 : [ 25 - (3x +2) ] =3^ .7
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1) x (x-2016) + 2015 (2016-x) = 0
x (x-2016) - 2015 (x- 2016) = 0
(x-2015)(x-2016) =0
\(\Rightarrow\orbr{\begin{cases}x-2015=0\\x-2016=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2015\\x=2016\end{cases}}}\)
Vậy x= 2015; 2016
2) -5x (x-15) + (15-x) = 0
-5x (x-15) - (x-15) =0
(-5x -1) (x-15) =0
\(\Rightarrow\orbr{\begin{cases}-5x-1=0\\x-15=0\end{cases}\Rightarrow\orbr{\begin{cases}-5x=1\\x=15\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{1}{5}\\x=15\end{cases}}}\)
Vậy x= -1/5; 15
3) 3x (3x-7) - (7-3x) =0
3x(3x-7) + (3x -7) =0
(3x+1) (3x-7) =0
\(\Rightarrow\orbr{\begin{cases}3x+1=0\\3x-7=0\end{cases}\Rightarrow\orbr{\begin{cases}3x=-1\\3x=7\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{1}{3}\\x=\frac{7}{3}\end{cases}}}\)
Vậy x= -1/3 ; 7/3
\(\left(\frac{2}{3}x-1\right)\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)
=>\(\frac{2}{3}x-1=0\) hoặc \(\frac{3}{4}x+\frac{1}{2}=0\)
+)Nếu \(\frac{2}{3}x-1=0\)
=>\(\frac{2}{3}x=1\Rightarrow x=\frac{3}{2}\)
+)Nếu \(\frac{3}{4}x+\frac{1}{2}=0\)
=>\(\frac{3}{4}x=-\frac{1}{2}\Rightarrow x=-\frac{2}{3}\)
Vậy \(x=\frac{3}{2}\) hoặc \(x=-\frac{2}{3}\)
\(2016:\left[25-\left(3x+2\right)\right]=9.7.2\)
\(\Leftrightarrow2016:\left(25-3x-2\right)=126\)
\(\Leftrightarrow23-3x=2016:126=16\)
\(\Leftrightarrow3x=23-16=7\)
\(\Leftrightarrow x=\frac{7}{3}\)
Bài làm
2016 : [ 25 - ( 3x + 2 ) ] = 9 . 7 . 2
2016 : [ 25 - ( 3x + 2 ) ] = 126
25 - ( 3x + 2 ) = 2016 : 126
25 - ( 3x + 2 ) = 16
3x + 2 = 25 - 16
3x + 2 = 9
3x = 7
x = 7/3
Vậy x = 7/3
# Học tốt #
Ta có: \(2016:\left[25-\left(3x+2\right)\right]=32\cdot7\)
\(\Leftrightarrow25-\left(3x+2\right)=9\)
\(\Leftrightarrow3x+2=16\)
\(\Leftrightarrow3x=14\)
hay \(x=\dfrac{14}{3}\)
2016 : [25 - (3x+2)]=32.7
25 - (3x+2)= 2016 : 224
25 - (3x+2)= 9
3x+2 = 16
3x=14
x=\(\dfrac{14}{3}\)
mux 2 nha moi ng
2016 : \(\left[25-\left(3x+2\right)\right]=3^7\)
<=> 25 - (3x + 2) = 2016 : 2187
<=> 25 - 3x - 2 = \(\dfrac{224}{243}\)
<=> -3x = \(\dfrac{224}{243}\) + 2 - 25
<=> -3x = \(\dfrac{-5365}{243}\)
<=> x = 7,359396433 \(\approx\) 7,4