Tính ( viết cách tính giùm mình nha ) \(\frac{15^{20}.9^{10}}{27^{12}.25^{10}}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: \(\left(-10\right)\cdot35+10\cdot\left(-12\right)-\left(-10\right)\)
\(=\left(-10\right)\cdot35+\left(-10\right)\cdot12-\left(-10\right)\)
\(=-10\left(35+12-1\right)=-10\cdot46=-460\)
b: \(20\cdot\left(-345\right)+\left(-20\right)\cdot\left(-315\right)\)
\(=20\cdot\left(-345\right)+20\cdot315\)
\(=20\left(-345+315\right)=-30\cdot20=-600\)
c: \(25\left(27-55\right)-27\left(25-55\right)\)
\(=25\cdot27-25\cdot55-27\cdot25+27\cdot55\)
\(=27\cdot55-25\cdot55=2\cdot55=110\)
d: \(25\cdot\left(-415\right)+9\cdot\left(-15\right)\cdot418\)
\(=-25\cdot415-9\cdot15\cdot418\)
\(=-5\left(5\cdot415+3\cdot9\cdot418\right)\)
\(=-5\left(2075+11286\right)=-5\cdot13361=-66805\)
e: \(5+\left(-8\right)\cdot3\)
=5-24
=-19
\(\frac{15^{20}.9^{10}}{27^{12}.25^{10}}=\frac{\left(3.5\right)^{20}.\left(3^2\right)^{10}}{\left(3^3\right)^{12}.\left(5^2\right)^{10}}=\frac{3^{20}.5^{20}.3^{20}}{3^{36}.5^{20}}=3^4=81\)
Lời giải:
$1+2+3+....+25$
$=(1+25)+(2+24)+(3+23)+(4+22)+(5+21)+(6+20)+(7+19)+(8+18)+(9+17)+(10+16)+(11+15)+(12+14)+13$
$=\underbrace{26+26+26+...+26}_{12}+13$
$=26\times 12+13=325$
a) Ta có:
\(\begin{array}{l}\frac{{ - 10}}{{18}} =\frac{{ - 10:2}}{{18:2}} = \frac{{ - 5}}{9};\,\,\,\\\frac{{10}}{{18}} = \frac{{10:2}}{{18:2}} =\frac{5}{9};\,\,\\\,\frac{{15}}{{ - 27}} =\frac{{15:(-3)}}{{ - 27:(-3)}} = \frac{{ - 5}}{9};\,\\ - \frac{{20}}{{36}} =- \frac{{20:4}}{{36:4}}= \frac{{ - 5}}{9}.\end{array}\)
Vậy những phân số nào biểu diễn số hữu tỉ \(\frac{{ - 5}}{9}\) là: \(\frac{{ - 10}}{{18}};\,\frac{{15}}{{ - 27}};\, - \frac{{20}}{{36}}.\)
b) Số đối của các số \(12;\,\frac{{ 4}}{9};\, - 0,375;\,\frac{0}{5};\,-2\frac{2}{5}\) lần lượt là: \( - 12;\,\frac{-4}{9};\,0,375;\,\frac{0}{5};\, 2\frac{2}{5}\).
\(A=\frac{2^{19}3^9+5.2^{18}3^9}{3^9.2^9.2^{10}+3^{10}4^{10}}=\frac{3^9\left(2^{19}+5.2^{18}\right)}{3^92^{19}+3^{10}2^{20}}=\frac{3^9\left(2^{19}+5.2^{18}\right)}{3^9\left(2^{19}+3.2^{20}\right)}=\frac{2^{19}+5.2^{18}}{2^{19}+3.2^{20}}=\frac{2^{18}\left(2+5\right)}{2^{18}\left(2+3.2^2\right)}\)
\(=\frac{2+5}{2+3.2^2}=\frac{7}{14}=\frac{1}{2}\)
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+34+25+26+27+28+29+30=475
\(\frac{15^{20}\cdot9^{10}}{27^{12}\cdot25^{10}}=\frac{3^{20}\cdot5^{20}\cdot3^{20}}{3^{36}\cdot5^{20}}=\frac{3^{40}}{3^{36}}=3^4=81\)
\(=\frac{3^{20}.5^{20}.3^{20}}{3^{36}.5^{20}}=\frac{3^{40}}{3^{36}}=3^4=81\)