Giai cac bất phương trình:
a) (x-3)(x-2)<0
b) (x+3)(x+4)(x2+2)\(\ge\) 0
c) \(\dfrac{x-1}{x-2}\) \(\ge\)0
d)\(\dfrac{x+3}{2-x}\)\(\ge\) 0
e) (x-3)(x-2)(x+1)<0
g) \(\dfrac{2}{x-1}\)<0
k) x2 +3x+2>0
m) x2+1<0
Bài 2 ) Giai phương trình
a)\(\)/x-1/=-3
b) /2x+1/=0
c)/3-2x/=4
d)/x+1/+3x=4
e) /x+1-4x/=5
g)...
Đọc tiếp
Giai cac bất phương trình:
a) (x-3)(x-2)<0
b) (x+3)(x+4)(x2+2)\(\ge\) 0
c) \(\dfrac{x-1}{x-2}\) \(\ge\)0
d)\(\dfrac{x+3}{2-x}\)\(\ge\) 0
e) (x-3)(x-2)(x+1)<0
g) \(\dfrac{2}{x-1}\)<0
k) x2 +3x+2>0
m) x2+1<0
Bài 2 ) Giai phương trình
a)\(\)/x-1/=-3
b) /2x+1/=0
c)/3-2x/=4
d)/x+1/+3x=4
e) /x+1-4x/=5
g) /x-1/+/x-3/=2
k)/x-1/+/x-2/+/x-3/=2
a: (x-3)(x-2)<0
=>x-2>0 và x-3<0
=>2<x<3
b: \(\left(x+3\right)\left(x+4\right)\left(x^2+2\right)\ge0\)
\(\Leftrightarrow\left(x+3\right)\left(x+4\right)\ge0\)
=>x>=-3 hoặc x<=-4
c: \(\dfrac{x-1}{x-2}\ge0\)
nên \(\left[{}\begin{matrix}x-2>0\\x-1\le0\end{matrix}\right.\Leftrightarrow x\in(-\infty;1]\cup\left(2;+\infty\right)\)
d: \(\dfrac{x+3}{2-x}\ge0\)
\(\Leftrightarrow\dfrac{x+3}{x-2}\le0\)
hay \(x\in[-3;2)\)