1.2+3.4+5.6+...+19.20
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![](https://rs.olm.vn/images/avt/0.png?1311)
a)Đặt \(A=\dfrac{6}{1.4}+\dfrac{6}{4.7}+\dfrac{6}{7.10}+...+\dfrac{6}{97.100}\)
\(3a=3-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{3}{7}+\dfrac{3}{7}-\dfrac{3}{10}+...+\dfrac{3}{97}-\dfrac{3}{100}\)
\(=3-\dfrac{3}{100}\)
\(=\dfrac{297}{100}\)
b)Đặt \(B=\dfrac{4}{1.3}+\dfrac{16}{3.5}+\dfrac{36}{5.7}+...+\dfrac{9604}{97.99}\)
\(=2b=\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{97.99}\)
\(2b=2-\dfrac{2}{3}+\dfrac{2}{3}-\dfrac{2}{5}+\dfrac{2}{5}-\dfrac{2}{7}+...+\dfrac{2}{97}-\dfrac{2}{99}\)
\(2b=2-\dfrac{2}{99}=\dfrac{198}{99}-\dfrac{2}{99}=\dfrac{196}{99}\)
c) Tương tự! Bạn tự làm nhé!
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt \(A=1.2+2.3+3.4+...+19.20\)
Ta có: \(A=1.2+2.3+3.4+...+19.20\)
\(3A=1.2.3+2.3.3+3.4.3+...+19.20.3\)
\(3A=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-1\right)+...+19.20.\left(21-1\right)\)
\(3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+19.20.21-18.19.20\)
\(3A=19.20.21\)
\(A=19.20.7\)
\(A=2660\)
\(1\cdot2+2\cdot3+...+19\cdot20=\frac{1\cdot2\cdot\left(3-0\right)+2\cdot3\cdot\left(4-1\right)+...+19\cdot20\cdot\left(21-17\right)}{3}\)
\(=\frac{1\cdot2\cdot3+2\cdot3\cdot4-1\cdot2\cdot3+...+19\cdot20\cdot21-18\cdot19\cdot20}{3}\)\(=\frac{19\cdot20\cdot21}{3}=2660\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 1/1.2 = 1- 1/2
1/3.4 = 1/3 - 1/4
...............
1/19.20 = 1/19 - 1/20
Cộng vế với vế ta đc:
A = 1- 1/20 = 19/20
\(A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{17.18}+\frac{1}{19.20}\)
\(A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{17}-\frac{1}{18}+\frac{1}{19}-\frac{1}{20}\)
\(A=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{17}+\frac{1}{19}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+..+\frac{1}{18}+\frac{1}{20}\right)\)
\(A=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{17}+\frac{1}{18}+\frac{1}{19}+\frac{1}{20}\right)-2\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{18}+\frac{1}{20}\right)\)
\(A=\left(1+\frac{1}{2}+...+\frac{1}{20}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{9}+\frac{1}{10}\right)\)
\(A=\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{19}+\frac{1}{20}\)
\(\frac{A}{B}=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
D=1.2+3.4+4.5+...+19.20
3D=1.2.(3-0)+2.3.(4-1)+4.5(6-3)+...+19.20.(21-18)
3D=1.2.3-0.1.2+2.3.4-1.2.3+4.5.6-3.4.5+...+19.20.21-18.19.20
3D=(1.2.3+2.3.4+3.4.5+...+19.20.21)-(0.1.2+1.2.3+2.3.4+...+18.19.20)
3D=19.20.21
3D=7890
D=2660
![](https://rs.olm.vn/images/avt/0.png?1311)
Tính tổng : A=1.2+2.3+3.4+..+19.20
3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 19.20.21
3A = 19.20.21
A = \(\frac{19.20.21}{3}=3990\)
Tính tổng : A=1.2+2.3+3.4+..+19.20
3a=1.2.3-1.2.3.+2.3.4-2.3.4+......+19.20.21
3a=19.20.21
a=19.20.21:3=3990
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
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\(M=1\cdot2+2\cdot3+3\cdot4+...+19\cdot20=\)
\(3\times M=1\cdot2\cdot3+2\cdot3\cdot3+....+19\cdot20\cdot3=\)
\(3\times M=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)+....+19\cdot20\cdot\left(21-18\right)=\)
\(3\times M=1\cdot2\cdot3+2\cdot3\cdot4+...+19\cdot20\cdot21-1\cdot2\cdot3-...-18\cdot19\cdot20=\)
\(3\times M=19\cdot20\cdot21\)
\(M=\frac{19\cdot20\cdot21}{3}\)
\(M=2660\)
D = 1.2+3.4+5.6+...+19.20
3D = 1.2(3-0) + 2.3(4-1) ...... 19.20 (21-18)
3D = 1.2.3-0.2.3.4-1 ......... 19.20.21-18
3D = ( 1.2.3+2.3.4+.....+19.20.21) - ( 0.1.2+ 1.2.3+.... + 18.19.20)
3D = 19.20.21
3D = 7980
D = 2660