(x+15)-125=57 : 55
720: [ 41-( 2x - 5 )= 23 .5
27- 3 ( x + 4 ) =23
2015x . 53 = 125
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(34 - 53 + 28) - (34 - 53 - 21)
= 34 - 53 + 28 - 34 + 53 + 21
= (34 - 34) - (53 - 53) + (28 + 21)
= 0 - 0 + 49
= 49
(23 - 15 + 38) - (-47 - 15 + 23)
= 23 - 15 + 38 + 47 + 15 - 23
= (23 - 23) - (15 - 15) + (38 + 47)
= 85
(125 + 49 - 37) - (49 + 125 - 228)
= 125 + 49 - 37 - 49 - 125 + 228
= (125 - 125) + (49 - 49) - (37 - 228)
= -(-191) = 191
720:[41-(2x-5)]=2^3.5
720:[41-2x+5]=40
[41+5-2x]=720:40
46-2x=18
2x=46-18
2x=28
x=14
a, 2x.4=128
2x=128:4
2x=32
2x=25
x=5
Vay x=5
b, x15=x
x=1
Vay x=1
a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)
=>\(\left[2\left(10-x\right)+51\right]:3=5\)
=>\(\left[2\left(10-x\right)+51\right]=15\)
=>\(2\left(10-x\right)=15-51=-36\)
=>10-x=-36/2=-18
=>\(x=10-\left(-18\right)=10+18=28\)
b: \(\left(x-12\right)-15=20-\left(17+x\right)\)
=>\(x-12-15=20-17-x\)
=>\(x-27=3-x\)
=>\(2x=30\)
=>\(x=\dfrac{30}{2}=15\)
c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)
=>\(720-\left[41-2x+5\right]=8\cdot5=40\)
=>\(\left[41-2x+5\right]=720-40=680\)
=>-2x+46=680
=>-2x=680-46=634
=>\(x=\dfrac{634}{-2}=-317\)
a. 23 . ( 42 - x ) = 46
42 - x = 46 : 23
42 - x = 2
x = 42 - 2
x = 40
b. 7x - 8 = 41
7x = 41 + 8
7x = 49
x = 49 : 7
x = 7
c. 125 - 5(x + 3) = 15
5(x + 3) = 125 - 15
5(x + 3) = 110
x + 3 = 110 : 5
x + 3 = 22
x = 22 - 3
x = 19
a) 23 . ( 42 - x) = 46 => 42 - x = 46 : 23 = 2
=> x = 42 - 2 = 40
b) 7x - 8 = 41 => 7x = 41 + 8 = 49 => x = 49 : 7 = 7
c) 125 - 5.(x+3) = 15 => 5.(x+3) = 125 - 15 = 110 => x + 3 = 110 : 5 =22
=> x = 22 - 3 = 19
a)23+3 𝑥 =125 | b) 70 – 5.(𝑥 - 3)= 45 | c) 20 + 5 𝑥 = 57:55
3 𝑥 +23=125 | 70−5 𝑥 +15=45 | 5 𝑥 +20=5755
𝑥=34 | 𝑥=8 | 𝑥=−104
275
\(\left(x+15\right)-125=5^7:5^5\)
\(\Rightarrow\left(x+15\right)-125=5^2\)
\(\Rightarrow\left(x+15\right)-125=25\)
\(\Rightarrow x+15=25+125\)
=> x+15=150
=> x=150-15
Vậy x=135.
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
=> 720:[41-(2x-5)]=8.5
=> 720:[41-(2x-5)]=40
=> 41-(2x-5)=720:40
=> 41-(2x-5)=18
=> 2x-5=41-18
=> 2x-5=23
=> 2x=23+5
=> 2x=28
=> x=28:2
Vậy x=14.
\(2^7-3.\left(x+4\right)=23\)
=> 128-3.(x+4)=23
=> 3.(x+4)=128-23
=> 3.(x+4)=105
=> x+4=105:3
=> x+4=35
=> x=35-4
Vậy x=31.
\(2015^x.5^3=125\)
=> 2015x.53=53
=> 2015x=53:53
=> 2015x=1
=> 2015x=20150
Vậy x=0.