Rút gọn : A = \(\frac{4^{10+}8^4}{4^{5+}8^8}\)
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VD
4
S
1 tháng 7 2018
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{-2}{6}=-\frac{1}{3}\)
1 tháng 7 2018
Ta có:\
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)
\(A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(A=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(A=-\frac{2}{6}=-\frac{1}{3}\)
NV
16 tháng 9 2015
\(=\frac{4^{10}+4^8}{4^5+4^{16}}=\frac{4^8\left(4^2+1\right)}{4^5\left(1+4^{11}\right)}=\frac{4^8\cdot17}{4^5.4194305}=\frac{4^3.17}{4194305}=\frac{1088}{4194305}\)ak thhif ra mình nhầm
29 tháng 7 2017
8^10 + 4^10 / 8^4 + 4^11
= (2^3)^10 + (2^2)^10 / (2^3)^4 + (2^2)^11
=2^30 + 2^20 / 2^12 +2^22
= 2^20(2^10 +1) / 2^12( 2^10 +1)
=2^20/210
= 2^8 = 256
10 tháng 8 2016
\(A=\frac{4^6.9^5+69.120}{8^4.3^{12}+6^{11}}=\frac{2^{12}.3^{10}+2^3.3^2.115}{2^{12}.3^{12}+\left(2.3\right)^{11}}=\frac{3^2.2^3\left(115+2^9.3^8\right)}{6^{11}\left(6+1\right)}=\frac{115+2^9.3^8}{6^8.3.7}\)
\(B=\frac{10^4+5.10^3+5^4}{25}=\frac{\left(10^2\right)^2+2.5^2.10^2+\left(5^2\right)^2}{25}=\frac{\left(10^2+5^2\right)^2}{25}=\frac{125^2}{25}=\frac{25.625}{25}=625\)
\(C=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{4^{10}.2^{10}+4^{10}}{4^4.4^7+4^4.2^4}=\frac{4^{10}\left(2^{10}+1\right)}{4^4.2^4\left(2^{10}+1\right)}=\frac{4^6}{2^4}=256\)
26 tháng 6 2019
\(\frac{8^{10}+4^{10}}{8^4+4^{10}}\)
\(=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{10}}\)
\(=\frac{2^{30}+2^{20}}{2^{12}+2^{20}}\)
\(=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(1+2^8\right)}\)
\(=\frac{2^8.\left(2^{10}+1\right)}{1+2^8}\)
\(=\frac{262400}{257}\)
26 tháng 6 2019
\(\frac{8^{10}+4^{10}}{8^4+4^{10}}=\frac{2^{30}+2^{20}}{2^{12}+2^{20}}=\frac{2^{12}.\left(2^{18}+2^{10}\right)}{2^{12}.\left(1+2^{10}\right)}\frac{2^{18}+2^{10}}{2^{10}+1}\)
F
1
TM
8 tháng 7 2016
\(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8\)
8 tháng 7 2016
Đặt A
\(A=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.\left(2^{18}+2^8\right)}{2^{12}.\left(1+2^{10}\right)}=2^8\)
DT
0
MT
1
TH
27 tháng 9 2018
\(M=\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(M=\frac{\left(2^2\right)^5\cdot\left(3^2\right)^4-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5}\)
\(M=\frac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)
\(M=\frac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)
\(M=\frac{-2}{6}=\frac{-1}{3}\)
\(\frac{4^{10}+8^4}{4^5+8^8}=\frac{4^5.4^5+8^4}{4^5+8^4.8^4}=\frac{4^5}{8^4}=\frac{\left(2^2\right)^5}{\left(2^3\right)^4}=\frac{2^{10}}{2^{12}}=\frac{2^{10}}{2^{10}.2^2}=\frac{1}{4}\)