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7 tháng 12 2016

3x4y2 + 3x3y2 + 3xy2 + 3y2

=(3x4y2 + 3x3y2) + (3xy2 + 3y2)

=3x3y2(x + 1) + 3y2(x + 1)

=(3x3y2 + 3y2)(x + 1)

=3y2(x3 + 1)(x + 1)

=3y2(x + 1)(x2 - x + 1)(x + 1)

=3y2(x + 1)2(x2 - x + 1)

13 tháng 12 2016

thank you

 

9 tháng 9 2020

           Bài làm :

 \(\text{a)}9\left(x+y-1\right)^2-4\left(2x+3y+1\right)^2\)

\(=\left(3x+3y-3\right)^2-\left(4x+6y+2\right)^2\)

\(=\left(3x+3y-3-4x-6y-2\right)\left(3x+3y-3+4x+6y+2\right)\)

\(=\left(-x-3y-5\right)\left(7x+9y-1\right)\)

 \(\text{b)}3x^4y^2+3x^3y^2+3xy^2+3y^2\)

\(=\left(3x^4y^2+3xy^2\right)+\left(3x^3y^2+3y^2\right)\)

\(=3xy^2\left(x^3+1\right)+3y^2\left(x^3+1\right)\)

\(=\left(3xy^2+3y^2\right)\left(x^3+1\right)\)

\(=3y^2\left(x+1\right)\left(x+1\right)\left(x^2-x+1\right)\)

\(=3y^2\left(x+1\right)^2\left(x^2-x+1\right)\)

 \(\text{c)}\left(x+y\right)^3-1-3xy\left(x+y-1\right)\)

\(=\left(x+y-1\right)\left[\left(x+y\right)^2+x+y+1\right]-3xy\left(x+y-1\right)\)

\(=\left(x+y-1\right)\left(x^2+2xy+y^2+x+y+1-3xy\right)\)

\(=\left(x+y-1\right)\left(x^2+x+y^2+y+1-xy\right)\)

\(d ) x^3+3x^2+3x+1-27z^3\)

\(=\left(x+1\right)^3-\left(3z\right)^3\)

\(=\left(x+1-3z\right)\left(x^2+2x+1+3xz+3z+9z^2\right)\)

25 tháng 7 2021

a, \(=\left(xy+1+x-y\right)\left(xy+1-x+y\right)\)

b, \(\left(x+y-x+y\right)[\left(x+y\right)^2+\left(x+y\right)\left(x-y\right)+\left(x-y\right)^2]\)

\(=2y[x^2+2xy+y^2+x^2-y^2+x^2-2xy+y^2]\)

\(=2y\left(3x^2+y^2\right)\)

c,\(=3\left(x+1\right)^2\left(x^2-x+1\right)y^2\)

25 tháng 7 2021

câu a, b áp dụng hằng đẳng thức rồi làm nha 

c) 3x4y+ 3x3y+ 3xy+ 3y2

= ( 3x4y+ 3x3y) + ( 3xy+ 3y)

= 3x3y( x + 1) + 3y( x + 1 )

= ( 3x3y+ 3y) ( x + 1 )

= 3y( x+ 1 ) ( x + 1 )

= 3y( x + 1 ) ( x2 - x + 1 ) ( x + 1 )

= 3y( x + 1 )( x2 - x + 1 )

1 tháng 10 2016

a) \(9\left(x+y-1\right)^2-4\left(2x+3y+1\right)^2\)

\(=\left(3x+3y-3\right)^2-\left(4x+6y+2\right)^2\)

\(=\left(3x+3y-3-4x-6y-2\right)\left(3x+3y-3+4x+6y+2\right)\)

\(=\left(-x-3y-5\right)\left(7x+9y-1\right)\)

b) \(3x^4y^2+3x^3y^2+3xy^2+3y^2\)

\(=\left(3x^4y^2+3xy^2\right)+\left(3x^3y^2+3y^2\right)\)

\(=3xy^2\left(x^3+1\right)+3y^2\left(x^3+1\right)\)

\(=\left(3xy^2+3y^2\right)\left(x^3+1\right)\)

\(=3y^2\left(x+1\right)\left(x+1\right)\left(x^2-x+1\right)\)

\(=3y^2\left(x+1\right)^2\left(x^2-x+1\right)\)

c) \(\left(x+y\right)^3-1-3xy\left(x+y-1\right)\)

\(=\left(x+y-1\right)\left[\left(x+y\right)^2+x+y+1\right]-3xy\left(x+y-1\right)\)

\(=\left(x+y-1\right)\left(x^2+2xy+y^2+x+y+1-3xy\right)\)

\(=\left(x+y-1\right)\left(x^2+x+y^2+y+1-xy\right)\)

a: \(\left(2x+3\right)^3=8x^3+36x^2+54x+27\)

b: \(\left(x-3y\right)^3=x^3-9x^2y+27xy^2-27y^3\)

26 tháng 8 2017

\(3x^4y^2+3x^3y^2+3xy^2+3y^2=3x^3y^2\left(x+1\right)+3y^2\left(x+1\right)\)

\(=\left(3x^3y^2+3y^2\right)\left(x+1\right)=3y^2\left(x^3+1\right)\left(x+1\right)\)

\(=3y^2\left(x+1\right)\left(x^2-x+1\right)\left(x+1\right)=3y^2\left(x^2-x+1\right)\left(x+1\right)^2\)