tinh nhanh\(\frac{-63^2}{13^2}+\frac{108^2}{13^2}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{-63^{^2}}{13^{^2}}\)+ \(\frac{108^{^2}}{13^{^2}}\)
= \(\frac{-3969}{169}\)+ \(\frac{11664}{169}\)
= \(\frac{-3969+11664}{169}\)
= \(\frac{7695}{169}\)
k mình nha
Mình cảm ơn bạn nhiều
Thank you very much!
(^_^)
\(\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}-\frac{2}{7}-\frac{2}{13}}\cdot\frac{\frac{3}{4}-\frac{3}{16}-\frac{3}{64}-\frac{3}{264}}{1-\frac{1}{4}-\frac{1}{16}-\frac{1}{64}}+\frac{5}{8}\)
\(=\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{2\left(\frac{1}{3}-\frac{1}{7}-\frac{1}{13}\right)}\cdot\frac{\frac{3}{4}\left(1-\frac{1}{4}-\frac{1}{16}-\frac{1}{64}\right)}{1-\frac{1}{4}-\frac{1}{16}-\frac{1}{64}}\)\(+\frac{5}{8}\)
\(\frac{1}{2}\cdot\frac{3}{4}+\frac{5}{8}=\frac{3}{8}+\frac{5}{8}=1\)
\(\frac{\frac{2}{3}-0,4-\frac{2}{7}+\frac{2}{11}}{\frac{13}{3}-2,6-\frac{13}{7}+\frac{13}{11}}=\frac{\frac{2}{3}-\frac{2}{5}-\frac{2}{7}+\frac{2}{11}}{\frac{13}{3}-\frac{13}{5}-\frac{13}{7}+\frac{13}{11}}=\frac{2\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}{13\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}=\frac{2}{13}\)
\(\frac{\frac{2}{3}-0,4-\frac{2}{7}+\frac{2}{11}}{\frac{13}{3}-\frac{2}{6}-\frac{13}{7}+\frac{13}{11}}=\frac{\frac{2}{3}-\frac{2}{5}-\frac{2}{7}+\frac{2}{11}}{\frac{13}{3}-\frac{13}{5}-\frac{13}{7}+\frac{13}{11}}=\frac{2\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}{13\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}=\frac{2}{13}\)
Vậy \(\frac{\frac{2}{3}-0,4-\frac{2}{7}+\frac{2}{11}}{\frac{13}{3}-2,6-\frac{13}{7}+\frac{13}{11}}=\frac{2}{13}\)
A = 1/5 + 1/13 + 1/14 + 1/15 + 1/60 + 1/61 + 1/62 + 1/63
Ta có : A = 1/5 + 1/13 + 1/14 + 1/15 + 1/60 + 1/61 + 1/62 + 1/63 < 1/5 + 1/12 + 1/12 + 1/12 + 1/60 + 1/60 + 1/60
= A < 1/5 + 1/4 + 1/20
= A < 1/2
Vậy A < 1/12
Ta có :
\(\frac{-63^2}{13^2}+\frac{108^2}{13^2}\)
\(=\frac{108^2-63^2}{13^2}\)
\(=\frac{\left(108-63\right)\left(108+63\right)}{13^2}\)
\(=\frac{45.171}{13^2}\)
\(=\frac{7695}{169}\)