Question

[Nguyễn Hữu Nguyên]

Tính \(\frac{5.4^{15}.9^9-3^{20}.4.8^9}{5.2^9.6^{19}-7.2^{29}.276}\)

Answer 1

[Akai Haruma]

Lời giải:
\(\frac{5.4^{15}.9^9-3^{20}.4.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-3^{20}.2^2.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\\ =\frac{5.2^{30}.3^{18}-3^{20}.2^{29}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\\ =\frac{2^{29}.3^{18}(5.2-3^2)}{2^{28}.3^{18}(5.3-7.2)}\\ =\frac{2^{29}.3^{18}}{2^{28}.3^{18}}=2\)