Tìm hóa trị:
AL(III)
a)AL2 (SO4)
b)AL Br3
c)AL (NO3)3
K
Khách
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Những câu hỏi liên quan
HH
3
29 tháng 12 2020
4Al+3O2----to--->2Al2O3
Al2O3 +3H2SO4----->Al2(SO4)3+3H2O
Al2(SO4)3+3BaCl2------>2AlCl3+3BaSO4
2AlCl3+3Ca(OH)2---->2Al(OH)3+3CaCl2
Al(OH)3+3HNO3---->Al(NO3)3+3H2O
2Al(NO3)3+3Mg----->3Mg(NO3)2+2Al
2Al+3H2SO4------->Al2(SO4)3+3H2
Al2(SO4)3+3Ca(OH)2------>2Al(OH)3+3CaSO4
2Al(OH)3-----to----->Al2O3+3H2O
2Al2O3----\(\dfrac{t^o}{criolit}\)---->4Al+3O2
2Al+2H2O+2NaOH------>2NaAlO2+3H2
K
29 tháng 12 2020
4Al+3O2\(\underrightarrow{t^o}\) 2Al2O3
Al2O3+H2SO4 —> Al2(SO4)3+3H2O
Al2(SO4)3+3BaCl2–>3BaSO4\(\downarrow\)+2AlCl3
AlCl3+3NaOH—>Al(OH)3\(\downarrow\)+3NaCl
Al(OH)3+HNO3 —>Al(NO3)3+NO2\(\uparrow\)+H2O
2Al(NO3)3+3Mg—>3Mg(NO3)2+2Al\(\downarrow\)
2Al+3H2SO4–>Al2(SO4)3+3H2\(\uparrow\)
Al2(SO4)3+6NaOH—>2Al(OH)3+3Na2SO4
2Al(OH)3\(\underrightarrow{t^o}\)Al2O3+3H2O
2Al2O3\(\xrightarrow[criolit]{đien.phan.nong.chay}\)
4Al+3O2
2Al+2NaOH+2H2O—>2NaAlO2+3H2
NN
2
18 tháng 12 2023
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)
\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
\(AlCl_3+3AgNO_3\rightarrow3AgCl+Al\left(NO_3\right)_3\)
\(Al\left(NO_3\right)_3+3KOH\rightarrow3KNO_3+Al\left(OH\right)_3\)
\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
H
18 tháng 12 2023
\(Al+\dfrac{3}{2}Cl_2\rightarrow AlCl_3\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\\ Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
21 tháng 12 2021
\(a,2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ Fe+H_2SO_4\to FeSO_4+H_2\\ FeSO_4+BaS\to BaSO_4\downarrow+FeS\\ FeS+2HCl\to FeCl_2+H_2\\ FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl\downarrow\)
\(b,2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ Al+NaOH+H_2O\to NaAlO_2+\dfrac{3}{2}H_2\)
TP
Thảo Phương
CTVVIP
12 tháng 8 2021
1.2FeO + \(\dfrac{1}{2}\)O2 → Fe2O3
2.2FexOy + \(\dfrac{3x-2y}{2}\) O2 → xFe2O3
3.2Al + 6HCl → 2AlCl3 + 3H2
4.Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2O
5.Al(OH)3 + 3HNO3 → Al(NO3)3 + 3H2O
TP
Thảo Phương
CTVVIP
12 tháng 8 2021
6. 2Al + 3H2SO4 → Al2(SO4)3 + 3H2
7.2C4H10 + 13O2 → 8CO2 + 10H2O
8. 2KMnO4 → K2MnO4 + MnO2 + O2
9.2Cu(NO3)2 → 2CuO + 4NO2 + O2
10.M2Ox + 2xHNO3 → 2M(NO3)x + xH2O
2
18 tháng 12 2021
\(Al+2HCl->AlCl_2+H_2\)
\(AlCl_2+3NaOH->Al\left(OH\right)_3+3NaCl\)
a, SO4 hóa trị II
b, Br hóa trị I
c, NO3 hóa trị I