K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

18 tháng 12 2021

\(Al+2HCl->AlCl_2+H_2\)

\(AlCl_2+3NaOH->Al\left(OH\right)_3+3NaCl\)

18 tháng 12 2021

Làm gì có \(AlCl_2\)?

21 tháng 12 2021

\(a,2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ Fe+H_2SO_4\to FeSO_4+H_2\\ FeSO_4+BaS\to BaSO_4\downarrow+FeS\\ FeS+2HCl\to FeCl_2+H_2\\ FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl\downarrow\)

\(b,2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ Al+NaOH+H_2O\to NaAlO_2+\dfrac{3}{2}H_2\)

29 tháng 12 2020

4Al+3O2----to--->2Al2O3

Al2O3 +3H2SO4----->Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2------>2AlCl3+3BaSO4

2AlCl3+3Ca(OH)2---->2Al(OH)3+3CaCl2

Al(OH)3+3HNO3---->Al(NO3)3+3H2O

2Al(NO3)3+3Mg----->3Mg(NO3)2+2Al

2Al+3H2SO4------->Al2(SO4)3+3H2

Al2(SO4)3+3Ca(OH)2------>2Al(OH)3+3CaSO4

2Al(OH)3-----to----->Al2O3+3H2O

2Al2O3----\(\dfrac{t^o}{criolit}\)---->4Al+3O2

2Al+2H2O+2NaOH------>2NaAlO2+3H2

29 tháng 12 2020

4Al+3O2\(\underrightarrow{t^o}\) 2Al2O3

Al2O3+H2SO4 —> Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2–>3BaSO4\(\downarrow\)+2AlCl3

AlCl3+3NaOH—>Al(OH)3\(\downarrow\)+3NaCl

Al(OH)3+HNO3 —>Al(NO3)3+NO2\(\uparrow\)+H2O

2Al(NO3)3+3Mg—>3Mg(NO3)2+2Al\(\downarrow\)

2Al+3H2SO4–>Al2(SO4)3+3H2\(\uparrow\)

Al2(SO4)3+6NaOH—>2Al(OH)3+3Na2SO4

2Al(OH)3\(\underrightarrow{t^o}\)Al2O3+3H2O

2Al2O3\(\xrightarrow[criolit]{đien.phan.nong.chay}\)

4Al+3O2

2Al+2NaOH+2H2O—>2NaAlO2+3H2

18 tháng 12 2023

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)

\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)

\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)

\(AlCl_3+3AgNO_3\rightarrow3AgCl+Al\left(NO_3\right)_3\)

\(Al\left(NO_3\right)_3+3KOH\rightarrow3KNO_3+Al\left(OH\right)_3\)

\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

18 tháng 12 2023

\(Al+\dfrac{3}{2}Cl_2\rightarrow AlCl_3\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\\ Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

3 tháng 4 2022

a) Al → Al2O3 → Al(NO3)3 → Al(OH)3 → Na[Al(OH)4] → Al(OH)3 → Al2O3 → Na[Al(OH)4] → Al2(SO4)3 → KAl(SO4)2.12H2O

4Al+3O2-to>2Al2O3

Al2O3+6HNO3->2Al(NO3)3+3H2O
Al(NO3)2+3NaOH->Al(OH)3+3NaNO3

Al(OH)3+NaOH->Na(Al(OH)4)

Na(Al(OH)4) + NH4Cl → Al(OH)3 + NH3 + NaCl + H2O

2Al(OH)3 -to>Al2O3+3H2O

Al2O3+3H2O+2NaOH->2Na(AlOH)4

2Na(Al(OH)4) + 4H2SO4 → Al2(SO4)3 + Na2SO4 + 8H2O

Al2(SO4)3+24H2O+K2SO4->2KAl(SO4)2.12H2O

 

 

3 tháng 4 2022

ok

30 tháng 12 2021

a)

\(Mg\left(OH\right)_2\underrightarrow{t^o}MgO+H_2O\)

\(MgO+H_2SO_4\rightarrow MgSO_4+H_2O\)

\(MgSO_4+BaCl_2\rightarrow BaSO_4\downarrow+MgCl_2\)

\(MgCl_2+2NaOH\rightarrow Mg\left(OH\right)_2\downarrow+2NaCl\)

b)

\(2Al_2O_3\xrightarrow[criolit]{npnc}4Al+3O_2\)

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\downarrow\)

\(4Al\left(NO_3\right)_3\underrightarrow{t^o}2Al_2O_3+12NO_2+3O_2\)

\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

13 tháng 12 2023

\(a,2Al_2O_3\rightarrow\left(đpnc,criolit\right)4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

13 tháng 12 2023

\(b,2Cu+O_2\rightarrow\left(t^o\right)2CuO\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\)