tinh A = ( 0,87 +6,4 ).(1,25.7 - 4/5.1,25)+31,64
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A = (0,87 + 0,64) . (1,25 . 7 + \(\dfrac{4}{5}\) . 1,25) + 31,64
A = 1,51 . [1,25 . (7 + \(\dfrac{4}{5}\))] + 31,64
A = 1,51 . (1,25 . 7,8) + 31,64
A = 1,51 . 9,75 + 31,64
A = 14,7225 + 31,64
A = 46,3625
A = \(\dfrac{3709}{80}\)
A= (0,87+0,64).(1,25.7+\(\dfrac{4}{5}\).1,25)+31,64
= 1,51.(1,25.(7+\(\dfrac{4}{5}\)))+31.64
= 1,51.(1,25.\(\dfrac{39}{5}\))+31.64
= 1,51.\(\dfrac{39}{4}\)+31.64
= \(\dfrac{5889}{400}\)+31,64
= 46,3625
A=[0,8x7+(0,8)2]x(1,25x7-0,8x1,25)+31,64
A=[0,8x7+0,8x0,8]x(1,25x(7-0,8))+31,64
A=[0,8x(7+0,8)]x(1,25x6,2)+31,64
A=[0,8x7,8]x7,75+31,64
A=6,24x7,75+31,64
A=48,36+31,64
A=80
Bài1:
\(\dfrac{\left(1,09-0,29\right).\left(\dfrac{5}{4}\right)}{18,9-16,65.\left(\dfrac{8}{9}\right)}=\dfrac{\dfrac{4}{5}.\left(\dfrac{5}{4}\right)}{\left(\dfrac{9}{8}\right).\left(\dfrac{8}{9}\right)}=1\)
Bài 1:
\(A=\dfrac{\left(1,09-0,29\right)\cdot\dfrac{5}{4}}{\left(18,9-16,65\right)\cdot\dfrac{8}{9}}=\dfrac{0,8\cdot1,25}{2,25\cdot\dfrac{8}{9}}=\dfrac{1}{2}\)
\(B=\left[0,8\cdot7+\left(0,8\right)^2\right]\left(1,25\cdot7-\dfrac{4}{5}\cdot1,25\right)+31,64\)
\(=0,8\cdot\left(7+0,8\right)\cdot1,25\left(7-0,8\right)+31,64\)
\(=0,8\cdot7,8\cdot1,25\cdot6,2+31,64\)
\(=6,24\cdot7,75+31,64=48,36+31,65=80\)
\(\Rightarrow A:B=\dfrac{1}{2}:80=\dfrac{1}{160}\)
Vậy A gấp 1/160 lần B
bài 2:
\(\dfrac{x}{4}-\dfrac{1}{y}=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{y}=\dfrac{x}{4}-\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{y}=\dfrac{x-2}{4}\)
=>y(x-2)=4
=>y và x-2 thuộc Ư(4) = {1;-1;2;-2;4;-4}
Ta có bẳng:
y | 1 | -1 | 2 | -2 | 4 | -4 |
x-2 | 4 | -4 | 2 | -2 | 1 | -1 |
x | 6 | -2 | 4 | 0 | 3 | 1 |
Vậy....
bài 3:
Ta có: x-y=x:y => x=xy+y=y(x+1) => x:y=y(x+1):y=x+1 (1)
Mà x:y=x-y (2)
Từ (1) và (2) => y = -1
Lại có: x=y(x+1) => x=(-1)(x+1) => x=-x-1 => 2x=-1 => x=\(\dfrac{-1}{2}\)
Vậy x=-1/2, y=-1
bài 4:
Ta có: x(x+y+z)+y(x+y+z)+z(x+y+z)=-5+9+5
=>(x+y+z)2=9
=>x+y+z=3 hoặc x+y+z=-3
Nếu x+y+z=3 => \(\left\{{}\begin{matrix}3x=-5\\3y=9\\3z=5\end{matrix}\right.\) =>\(\left\{{}\begin{matrix}x=\dfrac{-5}{3}\\y=3\\z=\dfrac{5}{3}\end{matrix}\right.\)
Nếu x+y+z=-3 => \(\left\{{}\begin{matrix}-3x=-5\\-3y=9\\-3z=5\end{matrix}\right.\)=>\(\left\{{}\begin{matrix}x=\dfrac{5}{3}\\y=-3\\z=\dfrac{-5}{3}\end{matrix}\right.\)
Vậy....
A = ( 0,87 +6,4 ).(1,25.7 - 4/5.1,25)+31,64
A= 7,2.7,75+31,64
A=55,8+31,64
A=87,44
(0,87 + 6,4) . (1,25 . 7 - 4/5 . 1,25) + 31,64
= 7,27 . (8,75 - 1) + 31,64
= 7,27 . 7,75 + 31,64
= 56,3425 + 31,64
= 87,9825