7/23*5/29+7/29*18/23-7/29
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-29.(85-47)-85.(47-29)
=-29.38-85.18
=-1102-1503
=-2605
-15.(23-29)+23-(15-29)
=-15.(-6)+23-(-14)
=90+23+14
=113+14
=127
-13.(55-29)+23.(15-29)
=-13.26+23.(-14)
=-338+(-322)
=-660
-10.(2+4)-5.(4-3)
=-10.6-5.1
=-60-5
=-65
\(a,-35.12-8.35\)
\(=\left(-35\right)\left(12+8\right)\)
\(=-700\)
\(b,-23.7-7.59-18.7\)
\(=7\left(-23-59-18\right)\)
\(7.\left(-100\right)=-700\)
\(b,115-\left(-12+29\right)\)
\(=115+12-29\)
\(=98\)
\(c,3.\left(-7\right)^2+5.\left(-4\right)^3\)
\(=3.49-5.64\)
\(=147-320\)
\(=-173\)
a)-35.12-8-35=-35(12+8)=-35.20=-700
b)23.(-7)-7.5+(-18).7=-7(23+59+18)=-7.100=-700
c)115-(-12+29)=115+12-29=98
d)\(3\left(-7\right)^2+5\left(-4\right)^3=3.7^2-5.4^3=3.49-5.64=147-320-173\)
x+126/216=204/216-24/216
=>x+126/216=108/216
=>x=108/216-126/216
=>x=-18/216
=>x=-1/12
1) $(-81)\cdot27-3^4\cdot(-77)$
$=(-81)\cdot27-81\cdot(-77)$
$=-81\cdot[27+(-77)]$
$=-81\cdot(27-77)$
$=-81\cdot(-50)$
$=81\cdot50$
$=4050$
2) $(-16)\cdot32-(-4)^2\cdot18$
$=(-16)\cdot32-16\cdot18$
$=-16\cdot(32+18)$
$=-16\cdot50$
$=-800$
3) $(-2)^4\cdot289-16\cdot189$
$=16\cdot289+16\cdot(-189)$
$=16\cdot[289+(-189)]$
$=16\cdot(289-189)$
$=16\cdot100$
$=1600$
4) $41\cdot(-18)+41\cdot(-81)-41$
$=1\cdot(-18)+41\cdot(-81)+41\cdot(-1)$
$=41\cdot[(-18)+(-81)+(-1)]$
$=41\cdot(-18-81-1)$
$=41\cdot(-99-1)$
$=41\cdot(-100)$
$=-4100$
5) $17\cdot(-37)-23\cdot37-46\cdot(-37)$
$=17\cdot(-37)+23\cdot(-37)-46\cdot(-37)$
$=-37\cdot(17+23-46)$
$=-37\cdot(40-46)$
$=-37\cdot(-6)$
$=37\cdot6$
$=222$
6) $-48+48\cdot(-78)+48\cdot(-21)$
$=48\cdot(-1)+48\cdot(-78)+48\cdot(-21)$
$=48\cdot[(-1)+(-78)+(-21)]$
$=48\cdot(-1-78-21)$
$=48\cdot(-79-21)$
$=48\cdot(-100)$
$=-4800$
7) $29\cdot(-13)+27\cdot(-29)+(-14)\cdot(-29)$
$=-29\cdot13+27\cdot(-29)+(-14)\cdot(-29)$
$=-29\cdot[13+27+(-14)]$
$=-29\cdot(40-14)$
$=-29\cdot26$
$=-754$
$\text{#}Toru$
a, x + 7/12 = 17/18 - 1/9
x + 7/12 = 15/18
x = 15/18 - 7/12
x = 1/4
b, 29/30 - ( 13/23 + x ) = 7/69
( 13/23 + x ) = 29/30 - 7/69
13/23 + x = 199/230
x = 199/230 - 13/23
x = 3/10
hok tốt
Bài 2
a: =>x=-23-7=-30
b: =>75:x=15
hay x=5
c: =>2(x+4)=80
=>x+4=40
hay x=36
d: \(\Leftrightarrow2^x\cdot11=88\)
hay x=3
Bài 3:
Có thể chia được nhiều nhất 12 tổ vì UCLN(180;132)=12
Khi đó, mỗi tổ có 15 nam và 11 nữ
7/23.5/29+7/29.18/23-7/29
=(7.5)/(23.29)+7/29.18/23-7/29
=7/29.5/23+7/29.18/23-7/29.1
=7/29.(5/23+18/23-1)
=7/29.(1-1)
=7/29.0
=0
\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)
\(=\frac{7}{29}\cdot0\)
\(=0\)