(5√7+7√5):√35
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6 x 6 = 36 63 : 7 = 9 7 x 5 = 35 6 x 7 = 42
7 x 7 = 49 48 : 6 = 8 35 : 7 = 5 42 : 6 = 7
5 x 5 = 25 49 : 7 = 7 35 : 5 = 7 42 : 7 = 6
6 x 6 = .36.... 63 : 7 = 9..... 7 x 5 = .35...... 6 x 7 = ..42...
7 x 7 = ..42... 48 : 6 = ..8... 35 : 7 = ...5.. 42 : 6 = ..7...
5 x 5 = ...25.. 49 : 7 = .7.... 35 : 5 = ...7.. 42 : 7 = ..6...
hok tốt
9 x 5 = 45
63 : 7 = 9
8 x 8 = 64
5 x 7 = 35
8 x 7 =56
3 x 8 = 24
40 : 5 = 8
5 x 5 = 25
7 x 5 = 35
7 x 8 =56
6 x 4 = 24
45 : 9 = 5
7 x 7 = 49
35 : 5 = 7
56 : 8 = 7
2 x 8 = 16
81 : 9 = 9
9 x 9 = 81
35 : 7 = 5
56 : 7 = 8
Học sinh nhẩm và ghi kết quả như sau:
7 x 5 = 35
7 x 6 = 42
7 x 2 = 14
7 x 4 = 28
35 : 7 =5
42 : 7 = 6
14 : 7 = 2
28: 7 =4
35 : 5 = 7
42 : 6 = 7
14 : 2 = 7
28 : 4 = 7
7 x 3 = 21 7 x 6 = 42 7 x 5 = 35 7 x 4 = 28
21 : 7 = 3 42 : 7 = 6 35 : 7 = 5 28 : 7 = 4
21 : 3 = 7 42 : 6 = 7 35 : 5 = 7 28 : 4 = 7
7 × 3 = 21 7 × 6 = 42 7 × 5 = 35. 7 × 4 = 28
21 : 7 = 3. 42 : 7 = 6. 35 : 7 = 5. 28 : 7 = 4
21 : 3 = 7. 42 : 6 = 7. 35 : 5 = 7. 28 : 4 = 7
2/7 + 3/5
= 10/35 + 21/35
= 31/35
31/35 - 2/7
= 31/35 - 10/35
= 21/35
= 3/5
31/35 - 2/5
= 31/35 - 14/35
= 17/35
3/5 + 2/7
= 21/35 + 10/35
= 31/35
2/7 + 3/5 = 10/35 + 21/35 = 31/35
31/35 - 2/7 = 31/35 - 10/35 = 21/35
31/35 - 2/5 = 31/35 - 21/35 = 10/35
3/5 + 2/7 = 21/35 + 10/35 = 31/35
\(\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left(\frac{157}{8}:\frac{7}{12}-\frac{53}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left[\left(\frac{157}{8}-\frac{53}{4}\right):\frac{7}{12}\right].\frac{4}{5}\)
\(=\left[\frac{51}{8}:\frac{7}{12}\right].\frac{4}{5}\)
\(=\frac{153}{14}.\frac{4}{5}\)
\(=\frac{306}{35}\)
\(\left(\frac{-2}{5}+\frac{3}{7}\right)-\left(\frac{4}{9}+\frac{12}{20}-\frac{13}{35}\right)+\frac{7}{35}\)
\(=\frac{1}{35}-\frac{212}{315}+\frac{7}{35}\)
\(=\frac{1}{35}+\frac{-212}{315}+\frac{7}{35}\)
\(=\frac{9}{315}+\frac{-212}{315}+\frac{63}{315}\)
\(=\frac{-140}{315}=\frac{-4}{9}\)
\(\dfrac{5\sqrt{7}+7\sqrt{5}}{\sqrt{35}}=\dfrac{\sqrt{35}\left(\sqrt{5}+\sqrt{7}\right)}{\sqrt{35}}=\sqrt{7}+\sqrt{5}\)