Tìm X biết: 8/x + 3 = 12 / 18
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1.8100
2. 34 x 18 + 18 x 66
= 18 x ( 34 + 66)
= 18 x 100 = 1800
3. X × ( 8 + 12) = 160 + 20 × 12
= X x 20 = 160 + 240
= X x 20 = 400
X = 400 : 20 = 20
4. X x 12 - X x 2 = 2020
(12 - 2) x X = 2020
10 x X = 2020
X = 2020 : 10 = 202
\(\frac{8}{12}\cdot x\cdot4-\frac{18}{12}\cdot x\cdot6=\frac{5}{12}\)
\(x\left(\frac{8}{12}\cdot4-\frac{18}{12}\cdot6\right)=\frac{5}{12}\)
\(x\left(\frac{32}{12}-\frac{108}{12}\right)=\frac{5}{12}\)
\(x\left(-\frac{19}{3}\right)=\frac{5}{12}\)
\(x=\frac{5}{12}\div\left(-\frac{19}{3}\right)=-\frac{5}{76}\)
Vậy \(x=-\frac{5}{76}\)
Chúc bạn học tốt ^^!!!
`x/8=4/(-32)`
`(4x)/32=(-4)/32`
`4x=-4`
`x=-1`
Vậy `x=-1`.
`b)x-7/18=3 5/12`
`x-7/18=41/12`
`x=41/12+7/18`
`x=137/36`
Vậy `x=137/36`
`c)-3/8. 2/5+(-3)/8. 9/5-(-3)/8. 6/5`
`=-3/8. 2/5-3/8. 9/5+3/8. 6/5`
`=3/8(-2/5-9/5+6/5)`
`=3/8.(-1)`
`=-3/8`
a) 2 . x + 12 = 36
2 . x = 36 - 12
2 . x = 24
x = 24 : 2
x = 12
Vậy x = 12
b) (x + 21) : 8 + 12 = 21
( x + 21 ) : 8 = 21 - 12
( x + 21 ) : 8 = 9
x + 21 = 9 . 8
x + 21 = 72
x = 72 - 21
x = 51
Vậy x = 51
c) (3 . x - 18) . (x - 9) = 0
\(\Rightarrow\begin{cases}3.x-18=0\\x-9=0\end{cases}\)
\(\Rightarrow\begin{cases}3.x=18\\x=0+9\end{cases}\)
\(\Rightarrow\begin{cases}x=18:3=6\\x=9\end{cases}\)
Vậy \(x\in\left\{6;9\right\}\)
a)
\(2x+12=36\)
\(\Rightarrow2\left(x+6\right)=36\)
\(\Rightarrow x+6=18\)
=> x = 12
Vậy x = 12
b)
\(\left(x+21\right):8+12=21\)
\(\Rightarrow\left(x+21\right):8=9\)
\(\Rightarrow x+21=72\)
=> x = 51
Vậy x = 51
c)
\(\left(3x-18\right)\left(x-9\right)=0\)
\(\Rightarrow3\left(x-6\right)\left(x-9\right)=0\)
\(\Rightarrow\left(x-6\right)\left(x-9\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-6=0\\x-9=0\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=6\\x=9\end{array}\right.\)
Vậy x = 6 ; x = 9
a) \(BCNN\left(3;8\right)=24\)
\(\Rightarrow x=24\) thỏa đề bài
b) \(BCNN\left(12;18;30\right)=180\)
\(\Rightarrow x=180\) thỏa đề bài
\(\left(\dfrac{103}{8}-\dfrac{193}{18}\right):x-\dfrac{40}{33}:\dfrac{8}{11}=\dfrac{5}{3}\)
\(\dfrac{155}{72}:x-\dfrac{5}{3}=\dfrac{5}{3}\)
\(\dfrac{155}{72}:x=\dfrac{5}{3}+\dfrac{5}{3}=\dfrac{10}{3}\)
\(x=\dfrac{155}{72}:\dfrac{10}{3}=\dfrac{31}{48}\)
vaayj.....
\(12\left(x-3\right)=5\left(x-1\right)+4\)
\(\Rightarrow12x-36=5x-5+4\)
\(\Rightarrow12x-5x=-5+4+36\)
\(\Rightarrow7x=35\)
\(\Rightarrow x=5\)
\(-6\left(x-7\right)+2\left(x+10\right)=x-18\)
\(-6x+42+2x+20=x-18\)
\(-6x+2x-x=-18-20-42\)
\(-5x=-80\)
\(x=16\)
\(7\left(2x-1\right)-12\left(x-5\right)=3\)
\(\Rightarrow14x-7-12x+60=3\)
\(\Rightarrow14x-12x=3-60+7\)
\(\Rightarrow2x=-50\)
\(\Rightarrow x=-25\)
\(\left|2x-1\right|=17\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=17\\2x-1=-17\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=9\\x=-8\end{cases}}\)
\(\left|8-3x\right|=14\)
\(\Leftrightarrow\orbr{\begin{cases}8-3x=14\\8-3x=-14\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=\frac{22}{3}\end{cases}}\)
\(\frac{8}{x}+3=\frac{12}{18}\)
\(\frac{8}{x}=\frac{12}{18}-3\)
\(\frac{8}{x}=\frac{2}{3}-3\)
\(\frac{8}{x}=\frac{2}{3}-\frac{3}{1}\)
\(\frac{8}{x}=\frac{2}{3}-\frac{9}{3}\)
\(\frac{8}{x}=-\frac{7}{3}\)
\(\Rightarrow x=8\cdot3:\left(-7\right)\)
\(\Rightarrow x=24:\left(-7\right)\)
\(\Rightarrow x=-\frac{24}{7}\)
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Còn nếu đề là: \(\frac{8}{x+3}=\frac{12}{18}\) thì ta làm như sau:
Theo bài ra, ta có \(\frac{8}{x+3}=\frac{2}{3}\)
\(\Rightarrow x+3=8\cdot3:2\)
\(\Rightarrow x+3=24:2\)
\(\Rightarrow x+3=12\)
\(\Rightarrow x=12-3\)
\(\Rightarrow x=9\)
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