Question

[_Banhdayyy_]

Mn giúp mik câu 3 với 8 ạ, camon nhiu:3333

Answer 1

[Nguyễn Lê Phước Thịnh]

1) Ta có: \(P=\left(\dfrac{1}{\sqrt{x}-1}+\dfrac{\sqrt{x}}{x-1}\right):\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}-1\right)\)

\(=\dfrac{\sqrt{x}+1+\sqrt{x}}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}:\dfrac{\sqrt{x}-\sqrt{x}+1}{\sqrt{x}-1}\)

\(=\dfrac{2\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\cdot\dfrac{\sqrt{x}-1}{1}\)

\(=\dfrac{2\sqrt{x}+1}{\sqrt{x}+1}\)

2) Thay \(x=4-2\sqrt{3}\) vào P, ta được:

\(P=\dfrac{2\left(\sqrt{3}-1\right)+1}{\sqrt{3}-1+1}=\dfrac{2\sqrt{3}-2+1}{\sqrt{3}}=\dfrac{2\sqrt{3}-1}{\sqrt{3}}=\dfrac{6-\sqrt{3}}{3}\)

Answer 2

[_Banhdayyy_]

giúp mik câu 3 ạ