20 Rút gọn
a) (2x-y)(2x+y)-(2x+y)^2 ; b) (x-3)(x^2+3x+9)-(5-x)^2
c) (2x+y)(4x^2-2xy+y^2)-(2x+y)^3 ; d) (3x-5)^2-(3x+5)^2
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10 tháng 7 2021
a) Ta có: \(A=\left(7-2x\right)\left(7+2x\right)+\left(2x+7\right)^2\)
\(=7-4x^2+4x^2+28x+49\)
\(=28x+56\)
b) Ta có: \(B=\left(4x-5\right)^2-\left(2x-1\right)\left(8x-5\right)\)
\(=16x^2-40x+25-\left(16x^2-10x-8x+5\right)\)
\(=16x^2-40x+25-16x^2+18x-5\)
\(=-22x+20\)
c) Ta có: \(C=\left(5x-3\right)^2-2\left(5x-3\right)\left(5-5x\right)+\left(5x-5\right)^2\)
\(=\left(5x-3\right)^2+2\cdot\left(5x-3\right)\left(5x-5\right)+\left(5x-5\right)^2\)
\(=\left(5x-3+5x-5\right)^2\)
\(=\left(10x-8\right)^2\)
\(=100x^2-160x+64\)
d) Ta có: \(D=\left(2a+3b-c\right)\left(2a-3b+c\right)-\left(4a^2-9b^2-c^2\right)\)
\(=\left[\left(2a+\left(3b-c\right)\right)\left(2a-\left(3b-c\right)\right)\right]-\left(4a^2-9b^2-c^2\right)\)
\(=4a^2-\left(3b-c\right)^2-4a^2+9b^2+c^2\)
\(=-9b^2+6bc-c^2+9b^2+c^2\)
=6bc
TP
2
4 tháng 9 2021
a: Ta có: \(2x\left(3x-1\right)-\left(x-3\right)\left(6x+2\right)\)
\(=6x^2-2x-6x^2-2x+18x+6\)
=14x+6
b: Ta có: \(\left(2x-3\right)^2-\left(2x+1\right)\left(2x-1\right)+3\left(2x-3\right)\)
\(=4x^2-12x+9-4x^2+1+6x-9\)
\(=-6x+1\)
c: Ta có: \(\left(x+y-1\right)^2-2\left(x+y-1\right)\left(x+y\right)+\left(x+y\right)^2\)
\(=\left(x+y-1-x-y\right)^2\)
=1
4 tháng 9 2021
a) \(2x\left(3x-1\right)-\left(x-3\right)\left(6x+2\right)=6x^2-2x-6x^2-2x+18x+6=14x+6\)
b) \(\left(2x-3\right)^2-\left(1+2x\right)\left(2x-1\right)+3\left(2x-3\right)=4x^2-12x+9-4x^2+1+6x-9=-6x+1\)
c) \(\left(x+y-1\right)^2-2\left(x+y-1\right)\left(x+y\right)+\left(x+y\right)^2=\left(x+y-1-x-y\right)^2=\left(-1\right)^2=1\)
N
19 tháng 11 2021
\(1,A=\dfrac{2x+1-x}{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}\cdot\left(x-\sqrt{x}-2\right)\\ A=\dfrac{\left(x+1\right)\left(\sqrt{x}+1\right)\left(\sqrt{x}-2\right)}{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}=\dfrac{\left(x+1\right)\left(\sqrt{x}-2\right)}{x-\sqrt{x}+1}\\ 2,\Leftrightarrow\left\{{}\begin{matrix}2a-b=1\\a-b=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=-1\\b=-3\end{matrix}\right.\Leftrightarrow y=-x-3\)
NC
1
20 tháng 8 2023
\(A=\left(\dfrac{2xy}{x^2-y^2}+\dfrac{x-y}{2x+2y}\right):\dfrac{x+y}{2x}+\dfrac{y}{y-x}\left(ĐKXĐ:x\ne\pm y\right)\)
\(A=\left(\dfrac{4xy}{2\left(x-y\right)\left(x+y\right)}+\dfrac{\left(x-y\right)^2}{2\left(x+y\right)\left(x-y\right)}\right):\dfrac{x+y}{2x}+\dfrac{y}{y-x}\)
\(=\dfrac{4xy+x^2-2xy+y^2}{2\left(x-y\right)\left(x+y\right)}.\dfrac{2x}{x+y}+\dfrac{y}{y-x}\)
\(=\dfrac{x^2+2xy+y^2}{2\left(x-y\right)\left(x+y\right)}.\dfrac{2x}{x+y}+\dfrac{y}{y-x}\)
\(\dfrac{2x\left(x+y\right)^2}{2\left(x-y\right)\left(x+y\right)^2}+\dfrac{y}{y-x}=\dfrac{x}{x-y}+\dfrac{y}{y-x}=\dfrac{x}{x-y}-\dfrac{y}{x-y}=\dfrac{x-y}{x-y}=1\)
10 tháng 9 2021
Sửa đề \(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(=8x^3+y^3-8x^3+y^3=2y^3\)
10 tháng 9 2021
\(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(=8x^3+y^3-8x^3+y^3\)
\(=2y^3\)
a) (2x-y)(2x+y)-(2x+y)^2
= 4x2-y2-(4x2+4xy+y2)
= 4x2-y2-4x2-4xy-y2
= -4xy
b) (x-3)(x^2+3x+9)-(5-x)^2
= (x3-27)-(25-10x+x2)
= x3-27-25+10x-x2
= x3-x2+10x-52
c) (2x+y)(4x^2-2xy+y^2)-(2x+y)^3
= (2x)3+y3- ((2x)3+3.4x2.y+3.y2.2x+y3)
= 8x3+y3-(8x3+12x2y+6xy2+y3)
= 8x3+y3-(8x3+12x2y+6xy2+y3)
= 8x3+y3-8x3-12x2y-6xy2-y3
=-12x2y-6xy2
d) (3x-5)^2-(3x+5)^2
= (3x-5-3x-5)(3x-5+3x+5)
= -10.6x
= -60x