Tinha nhanh ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x125125 x 127 -127127 x 125 )
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Đề bài có lẽ sai thừa số thứ hai phải là 125125x127-127127x125
Khi đó thừa số thứ hai sẽ là
125x1001x127-127x1001x125=0
Tích trên sẽ bằng 0
( 1 + 3 + 5 + 7 +... + 2003 + 2005 ) x ( 125125 x 127 - 127127 x 125 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 125 x 1001 x 127 - 127 x 1001 x 125 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x 0
= 0
~ Thiên Mã ~
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( 1+3+5+7+…+2003+2005) x (125 125 x 127 – 127 127 x 125)
= ( 1+3+5+7+…+2003+2005) x (125 x 1001 x 127 – 127 x 1001x 125)
= ( 1+3+5+7+…+2003+2005) x 0 = 0
a. Vì 125 125x127 – 127 127x125 = 1001x125x127 – 1001x127x125 = 0
nên : (1+3+5+...+2005)(125 125x127 – 127 127x125) = 0
b.
19 , 8 : 0 , 2 x 44 , 44 x 2 x 13 , 2 : 0 , 25 3 , 3 x 88 , 88 : 0 , 5 x 6 , 6 : 0 , 125 x 5 = 19 , 8 x 5 x 88 , 88 x 13 , 2 x 4 3 , 3 x 88 , 88 x 2 x 6 , 6 x 8 x 5 = 19 , 8 x 5 x 88 , 88 x 13 , 2 x 4 3 , 3 x 88 , 88 x 13 , 2 x 4 x 2 x 5 = 19 , 8 3 , 3 x 2 = 3
Vì 125 125x127 – 127 127x125 = 1001x125x127 – 1001x127x125 = 0
nên : (1+3+5+...+2005)(125 125x127 – 127 127x125) = 0
Ta có:
(1+3+5+...+2005)x(125125x127-127127x125)
=(1+3+5+...+2005)x(125x1001x127-127x1001x125)
=(1+3+5+...+2005)x0
=0
a+b=10
a+c=25
b+c=18
a+b=10
a+c=25
b+c=18
a+b=10
a+c=25
b+c=18
a+b=10
a+c=25
b+c=18
a+b=10
a+c=25
b+c=18
a+b=10
a+c=25
b+c=18
a+b=10
a+c=25
b+c=18
(1+3+5+7+...+2003+2005)×(125125×127-127127×125)
=(1+3+5+7+...+2003+2005)×0
=0
Ủng hộ nhé
( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x 125125 x127 - 127127 x 125
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 125 x 1001 x 127 ) - ( 127 x 1001 x 125 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x 0
= 0